제출 #568945

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
568945		zaneyu	Two Transportations (JOI19_transportations)	C++14	100 / 100	900 ms	72304 KiB

Azer

#include "Azer.h"
#include<bits/stdc++.h>
using namespace std;
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
typedef tree<long long,null_type,less_equal<long long>,rb_tree_tag,tree_order_statistics_node_update> indexed_set;
#pragma GCC optimize("Ofast")
//#pragma GCC target("avx2")
//order_of_key #of elements less than x
// find_by_order kth element
using ll=long long;
using ld=long double;
using pii=pair<int,int>;
#define f first
#define s second
#define pb push_back
#define REP(i,n) for(int i=0;i<n;i++)
#define REP1(i,n) for(int i=1;i<=n;i++)
#define FILL(n,x) memset(n,x,sizeof(n))
#define ALL(_a) _a.begin(),_a.end()
#define sz(x) (int)x.size()
#define SORT_UNIQUE(c) (sort(c.begin(),c.end()),c.resize(distance(c.begin(),unique(c.begin(),c.end()))))
const ll maxn=5e5+5;
const ll maxlg=__lg(maxn)+2;
const ll INF64=4e18;
const int INF=0x3f3f3f3f;
const int MOD=1e9+7;
const ld PI=acos(-1);
const ld eps=1e-6;
#define lowb(x) x&(-x)
#define MNTO(x,y) x=min(x,(__typeof__(x))y)
#define MXTO(x,y) x=max(x,(__typeof__(x))y)
template<typename T1,typename T2>
ostream& operator<<(ostream& out,pair<T1,T2> P){
    out<<P.f<<' '<<P.s;
    return out;
}
template<typename T>
ostream& operator<<(ostream& out,vector<T> V){
    REP(i,sz(V)) out<<V[i]<<((i!=sz(V)-1)?" ":"");
    return out;
}
namespace {

    int n;
    vector<pii> v[maxn];
    int dist[maxn];
    priority_queue<pii,vector<pii>,greater<pii>> pq;
    bool done[maxn];
    void relax(int u){
        done[u]=1;
        for(auto x:v[u]){
            MNTO(dist[x.f],dist[u]+x.s);
        }
    }
    int cnt,idx,mn,p,pv;
    int val=0;
    void send(){
        mn=INF+1;
        REP(i,n){
            if(!done[i]){
                if(mn>dist[i]){
                    mn=dist[i];
                    p=i;
                }
            }
        }
        if(mn==INF+1){
            return;
        }
        mn-=pv;
        MNTO(mn,511);
        REP(i,9) SendA((mn>>(8-i))&1);
        idx=1;
    }
}  

void InitA(int N, int A, std::vector<int> U, std::vector<int> V,
           std::vector<int> C) {
    n=N;
    REP(i,A){
        v[U[i]].pb({V[i],C[i]});
        v[V[i]].pb({U[i],C[i]});
    }
    REP(i,n) dist[i]=INF;
    dist[0]=0;
    pv=0;
    relax(0);
    send();
}
void ReceiveA(bool x) {
    val=val*2+x;
    ++cnt;
    if(idx==1){
        if(cnt==9){
            if(mn<=val){
                REP(i,11) SendA((p>>(10-i))&1);
                pv+=mn;
                relax(p);
                send();
            }
            else{
                pv+=val;
                idx=2;
            }
            cnt=0;
            val=0;
        }
    }
    else if(idx==2){
        if(cnt==11){
            dist[val]=pv;
            relax(val);
            send();
            cnt=0;
            val=0;
        }
    }
}

std::vector<int> Answer() {
    vector<int> ans;
    REP(i,n) ans.pb(dist[i]);
    return ans;
}

Baijan

#include "Baijan.h"
#include<bits/stdc++.h>
using namespace std;
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
typedef tree<long long,null_type,less_equal<long long>,rb_tree_tag,tree_order_statistics_node_update> indexed_set;
#pragma GCC optimize("Ofast")
//#pragma GCC target("avx2")
//order_of_key #of elements less than x
// find_by_order kth element
using ll=long long;
using ld=long double;
using pii=pair<int,int>;
#define f first
#define s second
#define pb push_back
#define REP(i,n) for(int i=0;i<n;i++)
#define REP1(i,n) for(int i=1;i<=n;i++)
#define FILL(n,x) memset(n,x,sizeof(n))
#define ALL(_a) _a.begin(),_a.end()
#define sz(x) (int)x.size()
#define SORT_UNIQUE(c) (sort(c.begin(),c.end()),c.resize(distance(c.begin(),unique(c.begin(),c.end()))))
const ll maxn=5e5+5;
const ll maxlg=__lg(maxn)+2;
const ll INF64=4e18;
const int INF=0x3f3f3f3f;
const int MOD=1e9+7;
const ld PI=acos(-1);
const ld eps=1e-6;
#define lowb(x) x&(-x)
#define MNTO(x,y) x=min(x,(__typeof__(x))y)
#define MXTO(x,y) x=max(x,(__typeof__(x))y)
template<typename T1,typename T2>
ostream& operator<<(ostream& out,pair<T1,T2> P){
    out<<P.f<<' '<<P.s;
    return out;
}
template<typename T>
ostream& operator<<(ostream& out,vector<T> V){
    REP(i,sz(V)) out<<V[i]<<((i!=sz(V)-1)?" ":"");
    return out;
}
namespace {

    int n;
    vector<pii> v[maxn];
    int dist[maxn];
    priority_queue<pii,vector<pii>,greater<pii>> pq;
    bool done[maxn];
    void relax(int u){
        done[u]=1;
        for(auto x:v[u]){
            MNTO(dist[x.f],dist[u]+x.s);
        }
    }
    int cnt,idx,mn,p,pv;
    int val=0;
    void send(){
        mn=INF+1;
        REP(i,n){
            if(!done[i]){
                if(mn>dist[i]){
                    mn=dist[i];
                    p=i;
                }
            }
        }
        if(mn==INF+1){
            return;
        }
        mn-=pv;
        MNTO(mn,511);
        REP(i,9) SendB((mn>>(8-i))&1);
        idx=1;
    }
}
void InitB(int N, int B, std::vector<int> S, std::vector<int> T,
           std::vector<int> D) {
    n=N;
    REP(i,B){
        v[S[i]].pb({T[i],D[i]});
        v[T[i]].pb({S[i],D[i]});
    }
    REP(i,n) dist[i]=INF;
    dist[0]=0;
    pv=0;
    relax(0);
    send();
}
void ReceiveB(bool y) {
    val=val*2+y;
    ++cnt;
    if(idx==1){
        if(cnt==9){
            if(mn<val){
                REP(i,11) SendB((p>>(10-i))&1);
                pv+=mn;
                relax(p);
                send();
            }
            else{
                pv+=val;
                idx=2;
            }
            cnt=0;
            val=0;
        }
    }
    else if(idx==2){
        if(cnt==11){
            dist[val]=pv;
            relax(val);
            send();
            cnt=0;
            val=0;
        }
    }
}

• Subtask 1: 6 / 6
• Subtask 2: 8 / 8
• Subtask 3: 8 / 8
• Subtask 4: 38 / 38
• Subtask 5: 14 / 14
• Subtask 6: 10 / 10
• Subtask 7: 16 / 16