Submission #568846

#TimeUsernameProblemLanguageResultExecution timeMemory
568846maomao90Super Dango Maker (JOI22_dango3)C++17
100 / 100
1222 ms940 KiB
// Hallelujah, praise the one who set me free // Hallelujah, death has lost its grip on me // You have broken every chain, There's salvation in your name // Jesus Christ, my living hope #include <bits/stdc++.h> #include "dango3.h" using namespace std; template <class T> inline bool mnto(T& a, T b) {return a > b ? a = b, 1 : 0;} template <class T> inline bool mxto(T& a, T b) {return a < b ? a = b, 1: 0;} #define REP(i, s, e) for (int i = s; i < e; i++) #define RREP(i, s, e) for (int i = s; i >= e; i--) typedef long long ll; typedef long double ld; #define FI first #define SE second typedef pair<int, int> ii; typedef pair<ll, ll> pll; typedef tuple<int, int, int> iii; #define ALL(_a) _a.begin(), _a.end() #define SZ(_a) (int) _a.size() #define pb push_back typedef vector<int> vi; typedef vector<ll> vll; typedef vector<ii> vii; typedef vector<iii> viii; #ifndef DEBUG #define cerr if (0) cerr #endif const int INF = 1000000005; const ll LINF = 1000000000000000005ll; const int MAXN = 400; const int MAXM = 25; namespace { int n, m; void solve(vi id, int m) { if (SZ(id) == n) { Answer(id); return; } int nm = m / 2; vi pref, suf; for (int i : id) { pref.pb(i); } reverse(ALL(id)); vi lv, rv; for (int i : id) { pref.pop_back(); vi vec; for (int j : pref) { vec.pb(j); } for (int j : suf) { vec.pb(j); } if (Query(vec) >= nm) { rv.pb(i); } else { suf.pb(i); lv.pb(i); } } solve(lv, nm); solve(rv, m - nm); } } void Solve(int N, int M) { n = N; m = M; vi id(n * m, 0); iota(ALL(id), 1); solve(id, m); }
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