This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
#pragma GCC target ("avx2")
#pragma GCC optimization ("Ofast")
#pragma GCC optimization ("unroll-loops")
typedef long long ll;
typedef vector<int> vi;
typedef pair<int, int> ii;
typedef vector<ii> vii;
typedef long double ld;
typedef pair<ll, ll> pll;
#define FOR(i, a, b) for(int i = a; i < b; i++)
#define ROF(i, a, b) for(int i = a; i >= b; i--)
#define ms memset
#define pb push_back
#define fi first
#define se second
ll MOD = 1000000007;
ll MOD1 = 998244353;
ll power(ll base, ll n){
if (n == 0) return 1;
if (n == 1) return base;
ll halfn = power(base, n/2);
if (n % 2 == 0) return (halfn * halfn) % MOD;
return (((halfn * halfn) % MOD) * base) % MOD;
}
ll inverse(ll n){
return power(n, MOD-2);
}
ll add(ll a, ll b){
return (a+b) % MOD;
}
ll mul(ll a, ll b){
a %= MOD;
return (a*b) % MOD;
}
ll gcd(ll a, ll b){
if (a == 1) return 1;
if (a == 0) return b;
return gcd(b%a, a);
}
ld pi = 3.141592653589793238;
struct segtree{
vector<ll> op, ans;
int sz = 0;
void init(int n){
sz = n;
op.assign(4*n, -1);
ans.assign(4*n, 0);
}
void prop(int v, int tl, int tr){
if (op[v] == -1 || tl == tr) return;
int tm = (tl+tr)/2;
op[2*v] = op[v];
op[2*v+1] = op[v];
ll len1 = tm-tl+1, len2 = tr-tm;
ans[2*v] = op[v] * len1;
ans[2*v+1] = op[v] * len2;
op[v] = -1;
}
void update(int v, int tl, int tr, int l, int r, int val){
prop(v, tl, tr);
if (l > r) return;
if (tl == l && tr == r){
op[v] = val;
ll len = tr-tl+1;
ans[v] = val * len;
return;
}
int tm = (tl+tr)/2;
update(2*v, tl, tm, l, min(r,tm), val);
update(2*v+1, tm+1, tr, max(l, tm+1), r, val);
ans[v] = ans[2*v] + ans[2*v+1];
}
void update(int l, int r, int val){
update(1, 0, sz-1, l, r, val);
}
ll get(int v, int tl, int tr, int l, int r){
prop(v, tl, tr);
if (l > r) return 0;
if (tl == l && tr == r) return ans[v];
int tm = (tl+tr)/2;
ll m1 = get(2*v, tl, tm, l, min(r, tm));
ll m2 = get(2*v+1, tm+1, tr, max(l, tm+1), r);
return m1 + m2;
}
ll get(int l, int r){
return get(1, 0, sz-1, l, r);
}
};
const int N = 100000;
vi dx = {0,0,-1,1};
vi dy = {1,-1,0,0};
void solve(){
int n; cin >> n;
vi x(n), y(n);
FOR(i,0,n) cin >> x[i] >> y[i];
int mx = 0;
FOR(d1,0,4){
vi used(n);
vector<ll> t(n,MOD); // time getting infected
vi d(n);
set<ii> st;
t[0] = 0;
//time getting infected, direction, start_point
st.insert({0,0});
used[0]=1;
while (!st.empty()){
ii cur = *st.begin();
st.erase(st.begin());
int u = cur.se;
used[u]=1;
FOR(j,0,n){
if (used[j]) continue;
FOR(d2,0,4){
if (d[u]==d2){
continue;
}
if (dx[d[u]] == dx[d2]){
continue;
}
if (dy[d[u]] == dy[d2]){
continue;
}
// x[u]+dx[d[u]]*k == x[j]+dx[d2]*k
ll X = (x[u]-x[j])/(dx[d2]-dx[d[u]]);
ll Y = (y[u]-y[j])/(dy[d2]-dy[d[u]]);
if (X==Y && abs(X)>=t[u]){
X = abs(X);
if (t[j] > X){
if (t[j] != MOD) st.erase({t[j],j});
t[j] = X;
d[j] = d2;
st.insert({t[j],j});
}
}
}
}
}
int cnt = 0;
FOR(i,0,n) cnt+=used[i];
mx=max(mx,cnt);
}
cout << mx << '\n';
}
int main(){
cout << fixed << setprecision(8);
ios::sync_with_stdio(false);
if (fopen("input.txt", "r")) {
freopen("input.txt", "r", stdin);
freopen("output.txt", "w", stdout);
}
int TC = 1;
//cin >> TC;
FOR(i, 1, TC+1){
//cout << "Case #" << i << ": ";
solve();
}
}
Compilation message (stderr)
fever.cpp:5: warning: ignoring '#pragma GCC optimization' [-Wunknown-pragmas]
5 | #pragma GCC optimization ("Ofast")
|
fever.cpp:6: warning: ignoring '#pragma GCC optimization' [-Wunknown-pragmas]
6 | #pragma GCC optimization ("unroll-loops")
|
fever.cpp: In function 'int main()':
fever.cpp:163:10: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
163 | freopen("input.txt", "r", stdin);
| ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~
fever.cpp:164:10: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
164 | freopen("output.txt", "w", stdout);
| ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~
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