Submission #56823

#	Time	Username	Problem	Language	Result	Execution time	Memory
56823		mraron	Match (CEOI16_match)	C++14	0 / 100	4 ms	620 KiB

match

/*
ID: noszaly1
TASK: {TASK}
LANG: C++11               
*/

//Noszály Áron 10o Debreceni Fazekas Mihály Gimnázium

#include<iostream>
#include<vector>
#include<map>
#include<set>
#include<cassert>
#include<cassert>
#include<unordered_map>
#include<unordered_set>
#include<functional>
#include<queue>
#include<stack>
#include<cstring>
#include<algorithm>
#include<cmath>
#include<sstream>
#include<iomanip>
#include<cstdio>
#include<cstdlib>
#include<numeric>
using namespace std;

#define all(x) (x).begin(), (x).end()
#define pb push_back
#define xx first
#define yy second
#define sz(x) (int)(x).size()
#define gc getchar
#define IO ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0)
#define mp make_pair

typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;

const double PI=acos(-1);

template<typename T> T getint() {
	T val=0;
	char c;
	
	bool neg=false;
	while((c=gc()) && !(c>='0' && c<='9')) {
		neg|=c=='-';
	}

	do {
		val=(val*10)+c-'0';
	} while((c=gc()) && (c>='0' && c<='9'));

	return val*(neg?-1:1);
}

ll mod=1e9+7;
ll p=31;

string t;

ll st[100001], en[100001];
map<int, vector<int>> lst;
string ans;

void solve(int L, int R) {
	if(L>R) return ;
	//cerr<<L<<" "<<lst[en[L]].back()<<" "<<R<<"\n";
	assert(lst[en[L]].back()<=R);
	
	int par=lst[en[L]].back();
	
	ans[L]='(';
	ans[par]=')';
	
	lst[en[L]].pop_back();
	
	solve(par+1, R);
	solve(L+1, par-1);
}

int main() {
	IO;
	cin>>t;
	
	stack<pair<char,ll>> s;
	
	int ind=0;
	for(auto i:t) {
		if(s.empty()) {
			st[ind]=-1;
		}else {
			st[ind]=s.top().yy;
		}
		
		if(!s.empty() && s.top().xx==i) {
			s.pop();
		}else {
			if(s.empty()) {
				s.push({i, i});
			}else {
				s.push({i, (i+p*s.top().yy)%mod});
			}
		}
		
		if(s.empty()) {
			en[ind]=-1;
		}else {
			en[ind]=s.top().yy;
		}
		
		ind++;
	}
	
	if(!s.empty()) {
		cerr<<"-1\n";
		return 0;
	}
	
	for(int i=0;i<sz(t);++i) {
		lst[st[i]].pb(i);
	}
	
	ans=string(sz(t), '*');
	
	solve(0, sz(t)-1);
	
	cout<<ans<<"\n";
	return 0;
}

• Subtask 1: 0 / 10
• Subtask 2: 0 / 27
• Subtask 3: 0 / 63