제출 #568052

#제출 시각아이디문제언어결과실행 시간메모리
568052abc864197532카멜레온의 사랑 (JOI20_chameleon)C++17
0 / 100
19 ms336 KiB
#include <bits/stdc++.h> using namespace std; #define lli long long int #define mp make_pair #define pb push_back #define eb emplace_back #define pii pair <int, int> #define X first #define Y second #define all(x) x.begin(), x.end() #define rall(x) x.rbegin(), x.rend() void abc() {cout << endl;} template <typename T, typename ...U> void abc(T a, U ...b) { cout << a << ' ', abc(b...); } template <typename T> void printv(T l, T r) { for (; l != r; ++l) cout << *l << " \n"[l + 1 == r]; } template <typename A, typename B> istream& operator >> (istream& o, pair<A, B> &a) { return o >> a.X >> a.Y; } template <typename A, typename B> ostream& operator << (ostream& o, pair<A, B> a) { return o << '(' << a.X << ", " << a.Y << ')'; } template <typename T> ostream& operator << (ostream& o, vector<T> a) { bool is = false; if (a.empty()) return o << "{}"; for (T i : a) {o << (is ? ' ' : '{'), is = true, o << i;} return o << '}'; } template <typename T> struct vv : vector <vector <T>> { vv(int n, int m, T v) : vector <vector <T>> (n, vector <T>(m, v)) {} vv() {} }; template <typename T> struct vvv : vector <vv <T>> { vvv(int n, int m, int k, T v) : vector <vv <T>> (n, vv <T>(m, k, v)) {} vvv() {} }; #ifdef Doludu #define test(args...) abc("[" + string(#args) + "]", args) #define owo freopen("input.txt", "r", stdin), freopen("output.txt", "w", stdout); #include "grader.cpp" #else #define test(args...) void(0) #define owo ios::sync_with_stdio(false); cin.tie(0) #include "chameleon.h" #endif const int mod = 1e9 + 7, N = 100000, logN = 20, K = 48763; void Solve(int n) { vector <vector <int>> g(n * 2 + 1), adj(n * 2 + 1); for (int i = 1; i <= n * 2; ++i) { for (int j = i + 1; j <= n * 2; ++j) { if (Query({i, j}) == 1) g[i].pb(j), g[j].pb(i), test(i, j); } } for (int i = 1; i <= n * 2; ++i) { if (g[i].size() == 2) { adj[i] = g[i]; } else if (g[i].size() == 3) { if (Query({i, g[i][0], g[i][1]}) == 1) adj[i].pb(g[i][2]); else if (Query({i, g[i][0], g[i][2]}) == 1) adj[i].pb(g[i][1]); else adj[i].pb(g[i][0]); } else { assert(g[i].size() == 1); } } vector <bool> vis_dfs(n * 2 + 1, false); vector <int> cyc; function <void(int)> dfs = [&](int v) { vis_dfs[v] = true; cyc.pb(v); for (int u : adj[v]) if (!vis_dfs[u]) dfs(u); }; vector <bool> vis(n * 2 + 1, false); for (int i = 1; i <= n * 2; ++i) if (!vis[i]) { int st = i; cyc.clear(), dfs(st); // check pair in the same cycle int m = cyc.size(); if (m >= 6) { test(cyc); for (int j = 0; j < m; ++j) if (!vis[cyc[j]]) { for (int t = (j + 3) % m, cnt = 0; cnt < (m - 4) / 2; ++cnt, t = (t + 2) % m) { if (Query({cyc[j], cyc[t]}) == 1) { Answer(cyc[j], cyc[t]); vis[cyc[j]] = true, vis[cyc[t]] = true; } } } } vector <int> p; for (int i = 1; i <= n * 2; ++i) if (!vis[i] && !count(all(cyc), i)) p.pb(i); for (int st : cyc) if (!vis[st]) { int l = 0, r = p.size(); while (r - l > 1) { int m = l + r >> 1; vector <int> now(p.begin() + l, p.begin() + m); int x = Query(now); now.pb(st); int y = Query(now); if (y == x) r = m; else l = m; } Answer(st, p[l]); vis[st] = vis[p[l]] = true; } } }

컴파일 시 표준 에러 (stderr) 메시지

chameleon.cpp: In function 'void Solve(int)':
chameleon.cpp:104:27: warning: suggest parentheses around '+' inside '>>' [-Wparentheses]
  104 |                 int m = l + r >> 1;
      |                         ~~^~~
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