제출 #567711

#제출 시각아이디문제언어결과실행 시간메모리
567711zaneyuTeam Contest (JOI22_team)C++14
37 / 100
2066 ms2132 KiB
/*input 4 1 2 3 1 2 3 1 2 3 1 2 3 */ #include<bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; //order_of_key #of elements less than x // find_by_order kth element typedef unsigned long long int ll; #define ld long double #define pii pair<ll,ll> typedef tree<pii, null_type, less<pii>, rb_tree_tag, tree_order_statistics_node_update> indexed_set; #define f first #define s second #define pb push_back #define REP(i,n) for(int i=0;i<n;i++) #define REP1(i,n) for(int i=1;i<=n;i++) #define FILL(n,x) memset(n,x,sizeof(n)) #define ALL(_a) _a.begin(),_a.end() #define sz(x) (int)x.size() const ll maxn=2e5+5; const ll maxlg=__lg(maxn)+2; const ll INF64=4e18; const int MOD=1e9+7; const int INF=0x3f3f3f3f; const ld PI=acos(-1); const ld eps=1e-9; #define lowb(x) x&(-x) #define MNTO(x,y) x=min(x,(__typeof__(x))y) #define MXTO(x,y) x=max(x,(__typeof__(x))y) #define SORT_UNIQUE(c) (sort(c.begin(),c.end()), c.resize(distance(c.begin(),unique(c.begin(),c.end())))) #define GET_POS(c,x) (lower_bound(c.begin(),c.end(),x)-c.begin())+1 template<typename T1,typename T2> ostream& operator<<(ostream& out,pair<T1,T2> P){ out<<P.f<<' '<<P.s; return out; } template<typename T> ostream& operator<<(ostream& out,vector<T> V){ REP(i,sz(V)) out<<V[i]<<((i!=sz(V)-1)?" ":""); return out; } ll mult(ll a,ll b){ if(a<0) a+=MOD; return (a*b)%MOD; } ll mypow(ll a,ll b){ if(b<=0) return 1; ll res=1LL; while(b){ if(b&1) res=mult(res,a); a=mult(a,a); b>>=1; } return res; } int arr[maxn][3]; bool del[maxn]; int32_t main(){ ios::sync_with_stdio(false),cin.tie(0); int n; cin>>n; REP(i,n) REP(j,3) cin>>arr[i][j]; REP(i,n){ int mx[3]={0,0,0}; REP(j,n){ if(del[j]) continue; REP(k,3) MXTO(mx[k],arr[j][k]); } REP(j,n){ if(del[j]) continue; int c=0; REP(k,3) if(arr[j][k]==mx[k]) ++c; if(c>=2){ del[j]=1; } } } int mx[3]={0,0,0}; REP(j,n){ if(del[j]) continue; REP(k,3) MXTO(mx[k],arr[j][k]); } if(!mx[0]) cout<<-1; else cout<<mx[0]+mx[1]+mx[2]; }
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