제출 #566915

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
566915		zaneyu	Jail (JOI22_jail)	C++14	61 / 100	5060 ms	28364 KiB

jail

/*input
2
7
1 2
2 3
3 4
4 5
3 6
6 7
2
4 1
5 7
4
1 2
1 3
1 4
3
2 3
3 4
4 2
*/
#include<bits/stdc++.h>
using namespace std;
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
typedef tree<long long,null_type,less_equal<long long>,rb_tree_tag,tree_order_statistics_node_update> indexed_set;
#pragma GCC optimize("Ofast")
//#pragma GCC target("avx2")
//order_of_key #of elements less than x
// find_by_order kth element
using ll=long long;
using ld=long double;
using pii=pair<int,int>;
#define f first
#define s second
#define pb push_back
#define REP(i,n) for(int i=0;i<n;i++)
#define REP1(i,n) for(ll i=1;i<=n;i++)
#define FILL(n,x) memset(n,x,sizeof(n))
#define ALL(_a) _a.begin(),_a.end()
#define sz(x) (int)x.size()
#define SORT_UNIQUE(c) (sort(c.begin(),c.end()),c.resize(distance(c.begin(),unique(c.begin(),c.end()))))
const ll maxn=2e5+5;
const ll maxlg=__lg(maxn)+2;
const ll INF64=4e18;
const int INF=0x3f3f3f3f;
const ll MOD=1e9+7;
const ld PI=acos(-1);
const ld eps=1e-6;
#define lowb(x) x&(-x)
#define MNTO(x,y) x=min(x,(__typeof__(x))y)
#define MXTO(x,y) x=max(x,(__typeof__(x))y)
template<typename T1,typename T2>
ostream& operator<<(ostream& out,pair<T1,T2> P){
    out<<P.f<<' '<<P.s;
    return out;
}
template<typename T>
ostream& operator<<(ostream& out,vector<T> V){
    REP(i,sz(V)) out<<V[i]<<((i!=sz(V)-1)?" ":"");
    return out;
}
ll mult(ll a,ll b){
    return a*b%MOD;
}
ll mypow(ll a,ll b){
    a%=MOD;
    if(a==0) return 0;
    if(b<=0) return 1;
    ll res=1LL;
    while(b){
        if(b&1) res=(res*a)%MOD;
        a=(a*a)%MOD;
        b>>=1;
    }
    return res;
}
int d;
bool hv[maxn];
bool wk=1;
vector<int> v[maxn];
int in[maxn],out[maxn];
int cur;
vector<int> vv[maxn];
bool dfs(int u,int p){
    if(u==d){
        return true;
    }
    for(int x:v[u]){
        if(x==p) continue;
        if(dfs(x,u)){
            if(in[x]) vv[in[x]].pb(cur);
            if(x!=d and out[x]) vv[cur].pb(out[x]);
            return true;
        }
    }
    return false;
}
int vis[maxn];
void dfs2(int u){
    vis[u]=1;
    for(int x:vv[u]){
        if(!vis[x]) dfs2(x);
        else if(vis[x]==1){
            wk=0;
            break;
        }
    }
    vis[u]=2;
}
void solve(){
    int n,m;
    cin>>n;
    wk=1;
    REP(i,n-1){
        int a,b;
        cin>>a>>b;
        --a,--b;
        v[a].pb(b),v[b].pb(a);
    }
    wk=1;
    cin>>m;
    vector<pii> asd;
    REP1(i,m){
        int a,b;
        cin>>a>>b;
        --a,--b;
        in[a]=i,out[b]=i;
        asd.pb({a,b});
    }
    REP(i,sz(asd)){
        int a=asd[i].f,b=asd[i].s;
        d=b;
        cur=i+1;
        dfs(a,-1);
        if(out[a]) vv[cur].pb(out[a]);
    }
    //REP1(i,m) cout<<i<<' '<<vv[i]<<'\n';
    REP1(i,m){
        if(!vis[i]) dfs2(i);
    }
    if(wk){
        cout<<"Yes\n";
    }
    else cout<<"No\n";
    REP(i,n) v[i].clear(),hv[i]=0,in[i]=out[i]=0;
    REP1(i,m) vv[i].clear(),vis[i]=0;
}
int main(){
    int t;
    cin>>t;
    while(t--) solve();
} 

• Subtask 1: 0 / 5
• Subtask 2: 5 / 5
• Subtask 3: 16 / 16
• Subtask 4: 28 / 28
• Subtask 5: 12 / 12
• Subtask 6: 0 / 11
• Subtask 7: 0 / 23