제출 #566305

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
566305		minhcool	Genetics (BOI18_genetics)	C++17	100 / 100	1397 ms	146580 KiB

genetics

#include<bits/stdc++.h>
using namespace std;
 
#define int long long
#define fi first
#define se second
#define pb push_back
#define mp make_pair
#define foru(i, l, r) for(int i = l; i <= r; i++)
#define ford(i, r, l) for(int i = r; i >= l; i--)
 
typedef pair<int, int> ii;
typedef pair<ii, int> iii;
typedef pair<ii, ii> iiii;
 
const int N = 4505;
 
const int oo = 1e18 + 7, mod = 1e9 + 7;
 
int n, m, K;
int a[N][N];
 
int ha[256];
 
int tol[N];
 
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
 
int rnd(int l, int r){
	int temp = rng() % (r - l + 1);
	temp = (temp + (r - l + 1)) % (r - l + 1);
	return temp + l;
}
 
int cntt[N][5];
bool ok[N];
 
int temp[N];
 
void process(){
	ha[0] = 1, ha[6] = 2, ha['T' - 'A'] = 3, ha[2] = 4;
	cin >> n >> m >> K;
	//cout << n << " " << m << " " << K << "\n";
	for(int i = 1; i <= n; i++){
		for(int j = 1; j <= m; j++){
			char c;
			cin >> c;
			a[i][j] = ha[c - 'A'];
			//cout << a[i][j] << "\n";
		}
	}
	int rem = n, itr = 0;
	while(1){
		//itr++;
		//cout << rem << "\n";
		//if(itr == 1000) break;
		int cnt = 0;
		for(int i = 1; i <= m; i++){
			for(int j = 1; j <= 4; j++) cntt[i][j] = 0;
		}
		for(int i = 1; i <= n; i++){
			temp[i] = rnd(0, 1);
			if(temp[i]){
				cnt++;
				for(int j = 1; j <= m; j++) cntt[j][a[i][j]]++;
			}
		}
		for(int i = 1; i <= n; i++){
			if(temp[i]) continue;
			if(ok[i]) continue;
			int sum = 0;
			for(int j = 1; j <= m; j++) sum += cntt[j][a[i][j]];
			if(sum != cnt * (m - K)){
				rem--;
				ok[i] = 1;
			}
		}
		//cout << rem << "\n";
		if(rem == 1) break;
	}
	//for(int i = 1; i <= n; i++) cout << ok[i];
	for(int i = 1; i <= n; i++) if(!ok[i]) cout << i << "\n";
	//int cnt = 0;
}
 
signed main(){
	ios_base::sync_with_stdio(0);
	process();
}

컴파일 시 표준 에러 (stderr) 메시지

genetics.cpp: In function 'void process()':
genetics.cpp:52:15: warning: unused variable 'itr' [-Wunused-variable]
   52 |  int rem = n, itr = 0;
      |               ^~~

• Subtask 1: 27 / 27
• Subtask 2: 19 / 19
• Subtask 3: 28 / 28
• Subtask 4: 26 / 26