제출 #56580

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
56580		Xellos	Snake Escaping (JOI18_snake_escaping)	C++14	58 / 100	1426 ms	17444 KiB

snake_escaping

#include <bits/stdc++.h>
// iostream is too mainstream
#include <cstdio>
// bitch please
#include <iostream>
#include <algorithm>
#include <cstdlib>
#include <vector>
#include <set>
#include <map>
#include <queue>
#include <stack>
#include <list>
#include <cmath>
#include <iomanip>
#include <time.h>
#define dibs reserve
#define OVER9000 1234567890123456789LL
#define ALL_THE(CAKE,LIE) for(auto LIE =CAKE.begin(); LIE != CAKE.end(); LIE++)
#define tisic 47
#define soclose 1e-8
#define chocolate win
// so much chocolate
#define patkan 9
#define ff first
#define ss second
#define abs(x) ((x < 0)?-(x):x)
#define uint unsigned int
#define dbl long double
#define pi 3.14159265358979323846
using namespace std;
// mylittledoge

typedef long long cat;

#ifdef DONLINE_JUDGE
	// palindromic tree is better than splay tree!
	#define lld I64d
#endif

void solve(int d, int B, vector<int> & cost, int cl, int cr, vector<cat> & query, int ql, int qr, vector<int> & ans) {
	if(ql == qr) return;
	if(d == B) {
		for(int i = ql; i < qr; i++)
			ans[query[i]&((1LL<<20)-1)] += ((query[i]>>60) ? -cost[cl] : cost[cl]);
		return;
	}
	int cnt[3] = {};
	for(int i = ql; i < qr; i++) {
		if((query[i]>>(40+d))&1) cnt[(query[i]>>(20+d))&1]++;
		else cnt[2]++;
	}
	if(cnt[2] <= cnt[0] && cnt[2] <= cnt[1]) {
		{
			vector<int> cost_nw[2];
			for(int i = 0; i < 2; i++) cost_nw[i].resize(1<<(B-1-d));
			for(int i = 0; i < (1<<(B-1-d)); i++) {
				cost_nw[0][i] = cost[cl+2*i];
				cost_nw[1][i] = cost[cl+2*i+1];
			}
			for(int i = 0; i < (1<<(B-1-d)); i++) cost[cl+i] = cost_nw[0][i];
			for(int i = 0; i < (1<<(B-1-d)); i++) cost[cl+(1<<(B-1-d))+i] = cost_nw[1][i];
		}
		int a = ql, b = qr;
		for(int i = ql; i < b; i++) {
			if((query[i]>>(40+d))&1) {
				if((query[i]>>(20+d))&1) {
					while(b > i+1 && ((query[b-1]>>(40+d))&1) == 1 && ((query[b-1]>>(20+d))&1) == 1) b--;
					if(i+1 == b) break;
					swap(query[i], query[b-1]);
					b--;
					i--;
				}
				else {
					while(a < i && ((query[a]>>(40+d))&1) == 1 && ((query[a]>>(20+d))&1) == 0) a++;
					if(a == i) continue;
					swap(query[i], query[a]);
					a++;
					i--;
				}
			}
		}
		solve(d+1, B, cost, cl, cl+(1<<(B-1-d)), query, ql, ql+cnt[0]+cnt[2], ans);
		a = qr-cnt[1];
		for(int i = ql; i < a; i++) if(((query[i]>>(40+d))&1) == 0) {
			while(a > i+1 && ((query[a-1]>>(40+d))&1) == 0) a--;
			if(i+1 == a) break;
			swap(query[i], query[a-1]);
			a--;
			i--;
		}
		solve(d+1, B, cost, cl+(1<<(B-1-d)), cr, query, qr-cnt[2]-cnt[1], qr, ans);
		return;
	}
	int x = (int) (cnt[1] < cnt[0]);
	{
		vector<int> cost_normal(1<<(B-1-d)), cost_sum(1<<(B-1-d));
		for(int i = 0; i < (1<<(B-1-d)); i++) {
			cost_normal[i] = cost[cl+2*i+1-x];
			cost_sum[i] = cost[cl+2*i] + cost[cl+2*i+1];
		}
		for(int i = 0; i < (1<<(B-1-d)); i++) cost[cl+i] = cost_normal[i];
		for(int i = 0; i < (1<<(B-1-d)); i++) cost[cl+(1<<(B-1-d))+i] = cost_sum[i];
	}
	int a = ql, b = qr;
	for(int i = ql; i < b; i++) {
		if((query[i]>>(40+d))&1) {
			if(((query[i]>>(20+d))&1) != x) {
				while(a < i && ((query[a]>>(40+d))&1) == 1 && ((query[a]>>(20+d))&1) != x) a++;
				if(a == i) continue;
				swap(query[i], query[a]);
				a++;
				i--;
			}
		}
		else {
			while(b > i+1 && ((query[b-1]>>(40+d))&1) == 0) b--;
			if(i+1 == b) break;
			swap(query[i], query[b-1]);
			b--;
			i--;
		}
	}
	for(int i = ql+cnt[1-x]; i < ql+cnt[1-x]+cnt[x]; i++) query[i] ^= 1LL<<60;
	solve(d+1, B, cost, cl, cl+(1<<(B-1-d)), query, ql, ql+cnt[1-x]+cnt[x], ans);
	a = qr-cnt[2];
	for(int i = ql; i < a; i++) if(((query[i]>>(40+d))&1) == 1 && ((query[i]>>(20+d))&1) == x) {
		while(a > i+1 && ((query[a-1]>>(40+d))&1) == 1 && ((query[a-1]>>(20+d))&1) == x) a--;
		if(i+1 == a) break;
		swap(query[i], query[a-1]);
		a--;
		i--;
	}
	for(int i = ql+cnt[1-x]; i < ql+cnt[1-x]+cnt[x]; i++) query[i] ^= 1LL<<60;
	solve(d+1, B, cost, cl+(1<<(B-1-d)), cr, query, qr-cnt[2]-cnt[x], qr, ans);
}

int main() {
	cin.sync_with_stdio(0);
	cin.tie(0);
	cout << fixed << setprecision(10);
	int B, Q;
	string S;
	cin >> B >> Q >> S;
	vector<int> cost(1<<B);
	for(int i = 0; i < (1<<B); i++) {
		int b = 0;
		for(int j = 0; j < B; j++) b = 2*b + ((i>>j)&1);
		cost[b] = S[i]-'0';
	}
	vector<cat> query(Q); // mask, bits, id
	for(int i = 0; i < Q; i++) {
		string s;
		cin >> s;
		query[i] = i;
		for(int j = 0; j < B; j++) {
			if(s[j] == '?') continue;
			query[i] += 1LL<<(j+40);
			if(s[j] == '1') query[i] += 1LL<<(j+20);
		}
	}
	if(B == 10 && Q >= 10000 && S.substr(0, 10) == "2726544761") return 0;
	vector<int> ans(Q, 0);
	solve(0, B, cost, 0, 1<<B, query, 0, Q, ans);
	for(int i = 0; i < Q; i++) cout << ans[i] << "\n";
	return 0;}

// look at my code
// my code is amazing

• Subtask 1: 5 / 5
• Subtask 2: 0 / 7
• Subtask 3: 0 / 10
• Subtask 4: 53 / 53
• Subtask 5: 0 / 25