제출 #565222

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
565222		maomao90	Two Transportations (JOI19_transportations)	C++17	100 / 100	792 ms	58168 KiB

Azer

// Hallelujah, praise the one who set me free
// Hallelujah, death has lost its grip on me
// You have broken every chain, There's salvation in your name
// Jesus Christ, my living hope
#include <bits/stdc++.h> 
#include "Azer.h"
using namespace std;

template <class T>
inline bool mnto(T& a, T b) {return a > b ? a = b, 1 : 0;}
template <class T>
inline bool mxto(T& a, T b) {return a < b ? a = b, 1: 0;}
#define REP(i, s, e) for (int i = s; i < e; i++)
#define RREP(i, s, e) for (int i = s; i >= e; i--)
typedef long long ll;
typedef long double ld;
#define FI first
#define SE second
typedef pair<int, int> ii;
typedef pair<ll, ll> pll;
typedef tuple<int, int, int> iii;
#define ALL(_a) _a.begin(), _a.end()
#define pb push_back
typedef vector<int> vi;
typedef vector<ll> vll;
typedef vector<ii> vii;
typedef vector<iii> viii;

#ifndef DEBUG
#define cerr if (0) cerr
#endif

namespace {
    const int NLOG = 11, CLOG = 9;
    const int INF = 1000000005;
    const int FINF = (1 << CLOG) - 2;
    const int MAXN = 200005;
    int n, m;
    vii adj[MAXN];
    queue<bool> qu;
    int vis[MAXN];
    vi dist;
    bool waitDist;
    int pd;

    int get(int bits) {
        int x = 0;
        REP (i, 0, bits) {
            x += qu.front() << i;
            qu.pop();
        }
        return x;
    }

    void send(int x, int bits) {
        REP (i, 0, bits) {
            SendA(x >> i & 1);
        }
    }

    ii dijkstra() {
        int u = -1, d = INF + 1;
        REP (i, 0, n) {
            if (vis[i]) continue;
            if (mnto(d, dist[i])) {
                u = i;
            }
        }
        return {u, d};
    }

    void relax(int u) {
        for (auto [v, w] : adj[u]) {
            mnto(dist[v], dist[u] + w);
        }
    }
}

void InitA(int N, int A, vi U, vi V, vi C) {
    n = N; m = A;
    REP (i, 0, m) {
        adj[U[i]].pb({V[i], C[i]});
        adj[V[i]].pb({U[i], C[i]});
    }
    dist = vi(n, INF);
    dist[0] = 0;
    auto [u, d] = dijkstra();
    send(d, CLOG);
    waitDist = 1;
}

void ReceiveA(bool x) {
    qu.push(x);
    bool found = 0;
    if (waitDist) {
        if (qu.size() == CLOG) {
            int nd = get(CLOG) + pd;
            auto [u, d] = dijkstra();
            cerr << "A " << nd << ' ' << d << '\n';
            if (d < nd) {
                send(u, NLOG);
                pd = d;
                vis[u] = 1;
                found = 1;
                relax(u);
            } else {
                waitDist = 0;
                pd = nd;
            }
        }
    } else {
        if (qu.size() == NLOG) {
            int u = get(NLOG);
            cerr << "A u " << u << '\n';
            dist[u] = pd;
            relax(u);
            vis[u] = 1;
            waitDist = 1;
            found = 1;
        }
    }
    if (found) {
        auto [u, d] = dijkstra();
        cerr << " A " << u << ' ' << d << '\n';
        if (u != -1) {
            send(min(d - pd, FINF), CLOG);
        }
    }
}

vi Answer() {
    return dist;
}

Baijan

// Hallelujah, praise the one who set me free
// Hallelujah, death has lost its grip on me
// You have broken every chain, There's salvation in your name
// Jesus Christ, my living hope
#include <bits/stdc++.h> 
#include "Baijan.h"
using namespace std;

template <class T>
inline bool mnto(T& a, T b) {return a > b ? a = b, 1 : 0;}
template <class T>
inline bool mxto(T& a, T b) {return a < b ? a = b, 1: 0;}
#define REP(i, s, e) for (int i = s; i < e; i++)
#define RREP(i, s, e) for (int i = s; i >= e; i--)
typedef long long ll;
typedef long double ld;
#define FI first
#define SE second
typedef pair<int, int> ii;
typedef pair<ll, ll> pll;
typedef tuple<int, int, int> iii;
#define ALL(_a) _a.begin(), _a.end()
#define pb push_back
typedef vector<int> vi;
typedef vector<ll> vll;
typedef vector<ii> vii;
typedef vector<iii> viii;

#ifndef DEBUG
#define cerr if (0) cerr
#endif

namespace {
    const int NLOG = 11, CLOG = 9;
    const int INF = 1000000005;
    const int FINF = (1 << CLOG) - 2;
    const int MAXN = 200005;
    int n, m;
    vii adj[MAXN];
    queue<bool> qu;
    int vis[MAXN];
    vi dist;
    bool waitDist;
    int pd;

    int get(int bits) {
        int x = 0;
        REP (i, 0, bits) {
            x += qu.front() << i;
            qu.pop();
        }
        return x;
    }

    void send(int x, int bits) {
        REP (i, 0, bits) {
            SendB(x >> i & 1);
        }
    }

    ii dijkstra() {
        int u = -1, d = INF + 1;
        REP (i, 0, n) {
            if (vis[i]) continue;
            if (mnto(d, dist[i])) {
                u = i;
            }
        }
        return {u, d};
    }

    void relax(int u) {
        for (auto [v, w] : adj[u]) {
            mnto(dist[v], dist[u] + w);
        }
    }
}

void InitB(int N, int A, vi U, vi V, vi C) {
    n = N; m = A;
    REP (i, 0, m) {
        adj[U[i]].pb({V[i], C[i]});
        adj[V[i]].pb({U[i], C[i]});
    }
    dist = vi(n, INF);
    dist[0] = 0;
    auto [u, d] = dijkstra();
    send(d, CLOG);
    waitDist = 1;
}

void ReceiveB(bool x) {
    qu.push(x);
    bool found = 0;
    if (waitDist) {
        if (qu.size() == CLOG) {
            int nd = get(CLOG) + pd;
            auto [u, d] = dijkstra();
            cerr << "B " << nd << ' ' << d << '\n';
            if (d <= nd) {
                send(u, NLOG);
                pd = d;
                vis[u] = 1;
                found = 1;
                relax(u);
            } else {
                waitDist = 0;
                pd = nd;
            }
        }
    } else {
        if (qu.size() == NLOG) {
            int u = get(NLOG);
            cerr << "B u " << u << '\n';
            dist[u] = pd;
            relax(u);
            vis[u] = 1;
            waitDist = 1;
            found = 1;
        }
    }
    if (found) {
        auto [u, d] = dijkstra();
        cerr << " B " << u << ' ' << d << '\n';
        if (u != -1) {
            send(min(d - pd, FINF), CLOG);
        }
    }
}

• Subtask 1: 6 / 6
• Subtask 2: 8 / 8
• Subtask 3: 8 / 8
• Subtask 4: 38 / 38
• Subtask 5: 14 / 14
• Subtask 6: 10 / 10
• Subtask 7: 16 / 16