제출 #564862

#제출 시각아이디문제언어결과실행 시간메모리
564862farhan132Event Hopping 2 (JOI21_event2)C++17
100 / 100
396 ms52768 KiB
/***Farhan132***/ //#pragma GCC optimize("Ofast") //#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,avx2,fma") //#pragma GCC optimization ("unroll-loops") //#pragma GCC optimize("fast-math") #include <bits/stdc++.h> using namespace std; typedef long long ll; typedef unsigned long long ull; typedef double dd; typedef vector<ll> vll; typedef pair<ll , ll> ii; typedef vector< ii > vii; typedef pair < pair < ll , ll > , pair < ll , ll > > cm; typedef tuple < ll, ll, ll > tp; #define ff first #define ss second #define pb push_back #define in insert #define f0(b) for(int i=0;i<(b);i++) #define f00(b) for(int j=0;j<(b);j++) #define f1(b) for(int i=1;i<=(b);i++) #define f11(b) for(int j=1;j<=(b);j++) #define f2(a,b) for(int i=(a);i<=(b);i++) #define f22(a,b) for(int j=(a);j<=(b);j++) #define sf(a) scanf("%lld",&a) #define sff(a,b) scanf("%lld %lld", &a , &b) #define pf(a) printf("%lld\n",a) #define pff(a,b) printf("%lld %lld\n", a , b) #define bug printf("**!\n") #define mem(a , b) memset(a, b ,sizeof(a)) #define front_zero(n) __builtin_clzll(n) #define back_zero(n) __builtin_ctzll(n) #define total_one(n) __builtin_popcount(n) #define clean fflush(stdout) //const ll mod = (ll) 998244353; const ll mod = (ll) 1e9 + 7; const ll maxn = (ll)1e8 + 5; const int nnn = 1048590; //const int inf = numeric_limits<int>::max()-1; const int inf = 1e9; //const ll INF = numeric_limits<ll>::max()-1; const ll INF = (ll)1e18; ll dx[]={0,1,0,-1}; ll dy[]={1,0,-1,0}; ll dxx[]={0,1,0,-1,1,1,-1,-1}; ll dyy[]={1,0,-1,0,1,-1,1,-1}; bool USACO = 0; mt19937 rng(chrono::system_clock::now().time_since_epoch().count()); #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace __gnu_pbds; template <typename T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; const ll N = 1e5 + 5; struct seg_tree{ struct typo{ ii p; void setup(ll n){ p = {n, 0}; } }; vector < typo > b; ll n; void init(ll l, ll r, ll node){ b[node].setup(n); return; } typo merge(typo a, typo b){ typo c; c.p = min(a.p , b.p); return c; } void build(ll l, ll r, ll node){ if(l == r){ init(l,r,node); return; } ll mid = (l + r)/2; ll n1 = 2*node; ll n2 = n1 + 1; build(l, mid , n1); build(mid+1, r, n2); b[node] = merge(b[n1] , b[n2]); return; } void build(ll _n){ n = _n; b.resize(4*n); build(1,n,1); // optional } void up(ll l, ll r, ll node, ll x, ll y, ii v){ if(y < l || x > r) return; if(x <= l && y >= r){ b[node].p = min(b[node].p, v); return; } ll mid = (l + r)/2; ll n1 = 2*node; ll n2 = n1 + 1; up(l , mid , n1 , x , y , v); up(mid + 1, r, n2, x, y , v); b[node] = merge(b[n1] , b[n2]); return; } void up(ll x, ii v){ up(1,n,1,x,x,v); return; } typo get(ll l, ll r, ll node, ll x, ll y){ if(y < l || x > r) return {{n, 0}}; if(x <= l && y >= r){ return b[node]; } ll mid = (l + r)/2; ll n1 = 2*node; ll n2 = n1 + 1; return merge(get(l , mid , n1 , x , y) , get(mid + 1, r , n2 , x , y)); } ll get(ll l, ll r){ return get(1,n,1,l,r).p.ss; } /* Final Check!!! 1. Typo, Okay? 2. Init Okay? (Build!!) 3. Merge, Okay? 4. Lazy Needed ? YES | NO (if NO, REMOVE anything related to lazy prop) 5. Dummy? 6. Check Update, Get, etc function's Merge, Lazy Prop , Init :D 7, Even after a WA, check for possible Out Of Bound/MLE/RE cases */ }T; ll par[20][N]; ll l[N], r[N]; ll range(ll x, ll y){ if(y < x) return 0; ll ans = 0; auto cur = T.get(x, y); if(!cur || r[cur] > y) return 0; ans++; for(ll i = 19; i >= 0; i--){ if(r[par[i][cur]] <= y) ans += (1 << i), cur = par[i][cur]; } return ans; } void solve(){ ll n , k; cin >> n >> k; vector < tuple < ll , ll , ll > > v; vector < ll > idx; for(ll i = 1; i <= n; i++){ cin >> l[i] >> r[i]; r[i]--; idx.pb(l[i]); idx.pb(r[i]); idx.pb(r[i]+1); } idx.pb(1e9 + 10); sort(idx.begin(), idx.end()); idx.erase(unique(idx.begin(), idx.end()), idx.end()); ll m = idx.size(); T.build(m); l[n+1] = r[n+1] = 1e9 + 10; for(ll i = 1; i <= n+1; i++){ l[i] = lower_bound(idx.begin(), idx.end(), l[i]) - idx.begin() + 1; r[i] = lower_bound(idx.begin(), idx.end(), r[i]) - idx.begin() + 1; if(i == n + 1) continue; v.pb({l[i], 1, i}); v.pb({r[i]+1, 0, i}); T.up(l[i], {r[i], i}); } sort(v.rbegin(), v.rend()); par[0][n+1] = n + 1; set < ii > s; s.in({r[n+1], n+1}); for(auto [val, t, i] : v){ if(t) s.in({r[i] , i}); else{ par[0][i] = (*s.begin()).ss; } } set < tuple < ll , ll , ll > > t; for(ll i = 1; i < 20; i++){ for(ll j = 1; j <= n+1; j++){ par[i][j] = par[i-1][par[i-1][j]]; } } ll ans = 1; s.clear(); auto cur = T.get(1, m); for(ll i = 19; i >= 0; i--){ if(r[par[i][cur]] < m) ans += (1 << i), cur = par[i][cur]; } if(ans < k){ cout << "-1\n"; return; } s.in({1, m-1}); vector < ll > res; for(ll i = 1; i <= n; i++){ auto pp = s.upper_bound({l[i], 1e9}); if(pp == s.begin()) continue; pp--; auto [L , R] = *pp; if(!(L <= l[i] && r[i] <= R)) continue; ans += range(L, l[i]-1) + range(r[i]+1, R) - range(L, R) + 1; if(ans < k){ ans -= range(L, l[i]-1) + range(r[i]+1, R) - range(L, R) + 1; continue; } s.erase({L, R}); if(L <= l[i]-1) s.in({L, l[i]-1}); if(r[i]+1 <= R) s.in({r[i]+1, R}); res.pb(i); } while(res.size() > k) res.pop_back(); for(auto u : res) cout << u << '\n'; return; } int main() { #ifdef LOCAL freopen("in", "r", stdin); freopen("out", "w", stdout); auto start_time = clock(); #else ios_base::sync_with_stdio(0); cin.tie(NULL); cout.tie(NULL); #endif ll T = 1, CT = 0; //cin >> T; while(T--){ solve(); } #ifdef LOCAL auto end_time = clock(); cerr<< "Execution time: "<<(end_time - start_time)*(int)1e3/CLOCKS_PER_SEC<<" ms\n"; #endif return 0; }

컴파일 시 표준 에러 (stderr) 메시지

event2.cpp: In function 'void solve()':
event2.cpp:255:20: warning: comparison of integer expressions of different signedness: 'std::vector<long long int>::size_type' {aka 'long unsigned int'} and 'll' {aka 'long long int'} [-Wsign-compare]
  255 |   while(res.size() > k) res.pop_back();
      |         ~~~~~~~~~~~^~~
event2.cpp: In function 'int main()':
event2.cpp:272:15: warning: unused variable 'CT' [-Wunused-variable]
  272 |     ll T = 1, CT = 0;  //cin >> T;
      |               ^~
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