Submission #564088

#	Time	Username	Problem	Language	Result	Execution time	Memory
564088		perchuts	Savez (COCI15_savez)	C++17	0 / 120	145 ms	65536 KiB

savez

#include <bits/stdc++.h>
#define all(x) x.begin(), x.end()
#define sz(x) (int) x.size()
#define endl '\n'
#define pb push_back
#define _ ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);

using namespace std;

using ll = long long;
using ull = unsigned long long;
using ii = pair<int,int>;
using iii = tuple<int,int,int>;

const int inf = 2e9+1;
const ll mod = 1e9+7;
const ll base = 101;

template<typename X, typename Y> bool ckmin(X& x, const Y& y) { return (y < x) ? (x=y,1):0; }
template<typename X, typename Y> bool ckmax(X& x, const Y& y) { return (x < y) ? (x=y,1):0; }

vector<int>sorted,qnt;

bool cmp(int a,int b){
    return qnt[a]>qnt[b];
}

vector<vector<ll>>hsh, revHsh;
vector<string>v;

ll mul[2000001];

void computeHash(int idx){
    int n = qnt[idx];
    hsh[idx].pb(ll(v[idx][0]-'A'));
    for(int i=1;i<n;++i){
        ll add = hsh[idx].back()*base+ll(v[idx][i]-'A');
        hsh[idx].pb(add);
        hsh[idx].back() %= mod;
    }
    revHsh[idx].pb(ll(v[idx][n-1]-'A'));
    for(int i=n-2;i>=0;--i){
        ll add = revHsh[idx].back()+mul[n-1-i]*ll(v[idx][i]-'A');
        revHsh[idx].pb(add);
        revHsh[idx].back() %= mod;
    }
}

unordered_map<int,int>dp;

int main(){_
    int n;cin>>n;
    v.resize(n), sorted.resize(n), qnt.resize(n);
    for(int i=0;i<n;++i){
        cin>>v[i];
        qnt[i] = sz(v[i]);
    }
    mul[0] = 1ll;
    for(int i=1;i<=2e6;++i)mul[i] = (mul[i-1]*base)%mod;

    iota(all(sorted),0);
    sort(all(sorted), cmp);

    hsh.resize(n), revHsh.resize(n);
    int best = 0;

    for(int i=0;i<n;++i){
        int idx = sorted[i];
        computeHash(idx);
        int m = qnt[idx];
        int me = int(hsh[idx][m-1]);
        int res = dp[me]+1;
        for(int j=0;j<m;++j)if(hsh[idx][j]==revHsh[idx][j])ckmax(dp[int(hsh[idx][j])], res); 
        ckmax(best, res);
    }
    cout<<best<<endl;
}

• Subtask 1: 0 / 12
• Subtask 2: 0 / 12
• Subtask 3: 0 / 12
• Subtask 4: 0 / 12
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• Subtask 10: 0 / 12