Submission #564070

#	Time	Username	Problem	Language	Result	Execution time	Memory
564070		OttoTheDino	Financial Report (JOI21_financial)	C++17	0 / 100	141 ms	23832 KiB

Main

#include <bits/stdc++.h>
using namespace std;

#define rep(i,s,e)                  for (int i = s; i <= e; ++i)
#define rrep(i,s,e)                 for (int i = s; i >= e; --i)
#define pb                          push_back
#define pf                          push_front
#define fi                          first
#define se                          second
#define all(a)                      a.begin(), a.end()
#define len(a)                      (int)a.size()
typedef long long ll;
typedef pair<int, int> ii;
typedef vector<ii> vii;
typedef vector<int> vi;
typedef vector<double> vd;
typedef vector<string> vs;
typedef vector<ll> vll;

map<int,vi> mp;

int main() {
    ios::sync_with_stdio(0);
    cin.tie(0);

    int n, d; cin >> n >> d;
    int a[n+1] = {};
    rep (i,1,n) {
        cin >> a[i];
        mp[a[i]].pb(i);
    }
    set<ii> st;
    vi rem[n+d+2];
    for (pair<int,vi> p : mp) {
        int val = p.fi;
        vi ids = p.se;
        rrep (j,len(ids)-1,0) {
            int x = ids[j];
            auto it = st.lower_bound({x+1,0});
            int s = x, e = x;
            if (it!=st.end() && (*it).fi-x<=d) {
                e = (*it).se;
                it = st.erase(it);
            }
            if (it!=st.begin() && x-(*--it).se<=d) {
                s = (*it).fi;
                e = max(e, (*it).se);
                st.erase(it);
            }
            st.insert({s,e});
            rem[e+d+1].pb(val);
        }
    }
    st.clear();
    st.insert({0,0});
    rep (i,1,n) {
        for (int r : rem[i]) {
            auto it = st.lower_bound({r,0});
            if (it!=st.end() && (*it).fi==r) st.erase(it);
        }
        auto it = st.lower_bound({a[i],0}); 
        if (it==st.end()) st.insert({a[i], (*--it).se+1});
        else if ((*it).fi!=a[i]) {
            if ((*it).se == (*--it).se+1) st.erase(next(it));
            st.insert({a[i], (*it).se+1});
        }
    }
    cout << (*st.rbegin()).se << "\n";

    return 0;
}

• Subtask 1: 0 / 14
• Subtask 2: 0 / 14
• Subtask 3: 0 / 20
• Subtask 4: 0 / 12
• Subtask 5: 0 / 5
• Subtask 6: 0 / 35