답안 #564010

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
564010 2022-05-18T12:21:41 Z maomao90 Wild Boar (JOI18_wild_boar) C++17
0 / 100
1 ms 852 KB
// Hallelujah, praise the one who set me free
// Hallelujah, death has lost its grip on me
// You have broken every chain, There's salvation in your name
// Jesus Christ, my living hope
#include <bits/stdc++.h> 
using namespace std;

template <class T>
inline bool mnto(T& a, T b) {return a > b ? a = b, 1 : 0;}
template <class T>
inline bool mxto(T& a, T b) {return a < b ? a = b, 1: 0;}
#define REP(i, s, e) for (int i = s; i < e; i++)
#define RREP(i, s, e) for (int i = s; i >= e; i--)
typedef long long ll;
typedef long double ld;
#define FI first
#define SE second
typedef pair<int, int> ii;
typedef pair<ll, ll> pll;
typedef tuple<int, int, int> iii;
typedef tuple<ll, ll, ll> tll;
#define ALL(_a) _a.begin(), _a.end()
#define pb push_back
typedef vector<int> vi;
typedef vector<ll> vll;
typedef vector<ii> vii;
typedef vector<iii> viii;

#ifndef DEBUG
#define cerr if (0) cerr
#endif

const int INF = 1000000005;
const ll LINF = 1000000000000000005ll;
const int MAXN = 2005;
const int MAXL = 100005;

int n, m, t, l, e;
vi adj[MAXN], radj[MAXN];
int w[MAXN];
int x[MAXL];
ll rd[MAXN][MAXN][4];
int rfi[MAXN][MAXN][4], rse[MAXN][MAXN][4];
ll dp[MAXL][4];

int par[MAXN][2];
ll dist[MAXN][MAXN][2];
int fi[MAXN][MAXN], se[MAXN][MAXN];
priority_queue<tll, vector<tll>, greater<tll>> pq;
void dijkstra(int s) {
    REP (i, 0, e) {
        dist[s][i][0] = dist[s][i][1] = LINF;
        fi[s][i] = se[s][i] = -1;
        par[i][0] = par[i][1] = -1;
    }
    dist[s][s][0] = w[s];
    pq.push(tll{w[s], s, 0});
    while (!pq.empty()) {
        auto [d, u, tp] = pq.top(); pq.pop();
        if (d != dist[s][u][tp]) continue;
        for (int v : adj[u]) {
            if (v > n && (v ^ 1) == par[u][tp]) {
                continue;
            }
            ll nd = d + w[v];
            if (mnto(dist[s][v][0], nd)) {
                if (par[v][0] != -1 && par[v][0] != u) {
                    dist[s][v][1] = dist[s][v][0];
                    par[v][1] = par[v][0];
                    pq.push(tll{dist[s][v][1], v, 1});
                }
                pq.push(tll{nd, v, 0});
                fi[s][v] = fi[s][u] == -1 ? v : fi[s][u];
                se[s][v] = u;
                par[v][0] = u;
            } else if (mnto(dist[s][v][1], nd)) {
                pq.push(tll{nd, v, 1});
                par[v][1] = u;
            }
        }
    }
}

int main() {
#ifndef DEBUG
    ios::sync_with_stdio(0), cin.tie(0);
#endif
    cin >> n >> m >> t >> l;
    e = n + 1;
    if (e & 1) {
        e++;
    }
    REP (i, 0, m) {
        int a, b, c; cin >> a >> b >> c;
        w[e] = c;
        adj[a].pb(e);
        adj[e].pb(b);
        radj[a].pb(e++);
        w[e] = c;
        adj[b].pb(e);
        adj[e].pb(a);
        radj[b].pb(e++);
    }
    REP (i, 1, e) {
        dijkstra(i);
    }
    REP (i, 1, n + 1) {
        REP (j, 1, n + 1) {
            if (i == j) continue;
            REP (z, 0, 4) {
                rd[i][j][z] = LINF;
            }
            //rd[i][j][3] = dist[i][j];
            for (int u : radj[i]) {
                for (int v : radj[j]) {
                    v ^= 1;
                    int tp = 0;
                    if (u == fi[i][j]) {
                        tp |= 1;
                    }
                    if (v == se[i][j]) {
                        tp |= 2;
                    }
                    if (mnto(rd[i][j][tp], dist[u][v][0])) {
                        rfi[i][j][tp] = u;
                        rse[i][j][tp] = v;
                    }
                }
            }
            REP (z, 0, 4) {
                cerr << i << ' ' << j << ' ' << z << ": " << rd[i][j][z] << ' ' << rfi[i][j][z] << ' ' << rse[i][j][z] << '\n';
            }
            cerr << ' ' << fi[i][j] << ' ' << se[i][j] << '\n';
        }
    }
    x[0] = -1;
    REP (i, 1, l + 1) {
        cin >> x[i];
    }
    while (t--) {
        int p, q; cin >> p >> q;
        x[p] = q;
        dp[1][0] = dp[1][1] = dp[1][2] = dp[1][3] = 0;
        REP (i, 2, l + 1) {
            int p = x[i - 2], u = x[i - 1], v = x[i];
            REP (j, 0, 4) {
                dp[i][j] = LINF;
                REP (k, 0, 4) {
                    if (p != -1 && (rse[p][u][k] ^ 1) == rfi[u][v][j]) continue;
                    mnto(dp[i][j], dp[i - 1][k] + rd[u][v][j]);
                }
                cerr << i << ' ' << j << ": " << dp[i][j] << '\n';
            }
        }
        ll ans = min({dp[l][0], dp[l][1], dp[l][2], dp[l][3]});
        if (ans >= LINF) {
            ans = -1;
        }
        cout << ans << '\n';
    }
    return 0;
}
# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 724 KB Output is correct
2 Correct 1 ms 852 KB Output is correct
3 Incorrect 1 ms 852 KB Output isn't correct
4 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 724 KB Output is correct
2 Correct 1 ms 852 KB Output is correct
3 Incorrect 1 ms 852 KB Output isn't correct
4 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 724 KB Output is correct
2 Correct 1 ms 852 KB Output is correct
3 Incorrect 1 ms 852 KB Output isn't correct
4 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 724 KB Output is correct
2 Correct 1 ms 852 KB Output is correct
3 Incorrect 1 ms 852 KB Output isn't correct
4 Halted 0 ms 0 KB -