# | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
---|---|---|---|---|---|---|---|
562737 | Mridul | Job Scheduling (CEOI12_jobs) | C++14 | 570 ms | 37788 KiB |
이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<bits/stdc++.h>
using namespace std;
#define ll long long int
#define pb push_back
#define inf 1e18
#define ff first
#define ss second
#define mod 1000000007
bool helper(vector<pair<int,int>> &jobs,vector<vector<int>> &ans,int n, int d, int m, int mid){
/*
Out here we need to count all the jobs that have frequency above
0 and need to be processed with following mid machines.
*/
auto temp = jobs;
vector<int> machines(mid, 0);
// Initially all the machines are unoccupied.
vector<int> days(m+1,0);
// we also need to maintain the no of days it took the job to complete.
int i = 1;
int j = 0;
int count = 0;
vector<vector<int>> res;
while(i<=m){
count++;
vector<int> t;
while(i<=m&&j<mid){
if(temp[i].first>0){
//reduce the frequency
temp[i].first--;
t.push_back(jobs[i].second);
//update the counter of intital date
//if not updated
if(days[temp[i].second]==0){
days[temp[i].second]=count;
}
//update the res vector
// if frequency ends, then update the total days
if(temp[i].first==0){
if(count-days[temp[i].second]>d)
return false;
else
days[temp[i].second] = count - days[temp[i].second];
i++;
}
j++;
}else{
i++;
}
}
t.push_back(0);
res.push_back(t);
j=j%mid;
}
if(count>n)
return false;
ans = res;
return true;
}
void binarySearch(vector<pair<int,int>> &jobs, vector<vector<int>> res,int n, int d, int m){
/*
We need to find the minimum number of machines such
that no job has to wait for more than 'd' days
since its commencement.
*/
int l = 1;
int r = m;
int ans;
while(l<=r){
int mid = l + (r-l)/2;
bool check = helper(jobs,res,n,d,m,mid);
if(check){
ans = mid;
r = mid-1;
}else{
l = mid+1;
}
}
cout<<ans<<endl;
while(res.size()<n){
res.push_back({0});
}
for(int i = 0;i<res.size();i++){
for(int j = 0;j<res[i].size();j++){
cout<<res[i][j]<<" ";
}
cout<<endl;
}
}
void solve(){
int n,d,m;
cin>>n>>d>>m;
vector<pair<int,int>> jobs(m+1);
vector<vector<int>> ans;
for(int i = 0;i<m;i++){
ll x;
cin>>x;
jobs[x].first++;
jobs[x].second = x;
}
sort(jobs.begin(),jobs.end());
binarySearch(jobs,ans, n, d, m);
}
int main()
{
int t=1;
//cin>>t;
while(t--)
{
solve();
}
return 0;
}
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