제출 #562488

#제출 시각아이디문제언어결과실행 시간메모리
562488ian2024밀림 점프 (APIO21_jumps)C++14
100 / 100
1216 ms50516 KiB
#include "jumps.h" #include <bits/stdc++.h> using namespace std; constexpr int kMaxLogN = 20; int N; vector<int> H; vector<vector<int>> L, R; vector<vector<int>> higher; void init(int _N, std::vector<int> _H) { N = _N; H = _H; H.insert(H.begin(), INT_MAX); H.insert(H.end(), INT_MAX); N += 2; L = R = higher = vector<vector<int>>(kMaxLogN, vector<int>(N)); stack<int> decreasing_height; for (int i = 0; i < N; ++i) { while (!decreasing_height.empty() && H[decreasing_height.top()] <= H[i]) { decreasing_height.pop(); } L[0][i] = decreasing_height.empty() ? i : decreasing_height.top(); decreasing_height.push(i); } while (!decreasing_height.empty()) { decreasing_height.pop(); } for (int i = N - 1; i >= 0; --i) { while (!decreasing_height.empty() && H[decreasing_height.top()] <= H[i]) { decreasing_height.pop(); } R[0][i] = decreasing_height.empty() ? i : decreasing_height.top(); decreasing_height.push(i); } for (int i = 0; i < N; ++i) { higher[0][i] = H[L[0][i]] > H[R[0][i]] ? L[0][i] : R[0][i]; } for (int j = 1; j < kMaxLogN; ++j) { for (int i = 0; i < N; ++i) { L[j][i] = L[j - 1][L[j - 1][i]]; R[j][i] = R[j - 1][R[j - 1][i]]; higher[j][i] = higher[j - 1][higher[j - 1][i]]; } } } int maximum_height_index(int l, int r) { for (int j = kMaxLogN - 1; j >= 0; --j) { if (R[j][l] <= r) { l = R[j][l]; } } return l; } int minimum_jumps(int A, int B, int C, int D) { ++A; ++B; ++C; ++D; if (B == C - 1) { return R[0][B] <= D ? 1 : -1; } int middle_tallest_index = maximum_height_index(B + 1, C - 1); if (H[B] > H[middle_tallest_index]) { return R[0][B] <= D ? 1 : -1; } int s = B; for (int j = kMaxLogN - 1; j >= 0; --j) { if (A <= L[j][s] && H[L[j][s]] < H[middle_tallest_index]) { s = L[j][s]; } } int jumps = 0; if (A <= L[0][s]) { if (R[0][L[0][s]] <= D) { return 1; } } else { for (int j = kMaxLogN - 1; j >= 0; --j) { if (H[higher[j][s]] <= H[middle_tallest_index]) { jumps |= (1 << j); s = higher[j][s]; } } if (s == middle_tallest_index) { return R[0][s] <= D ? jumps + 1 : -1; } if (0 < L[0][s] && R[0][L[0][s]] <= D) { return jumps + 2; } } for (int j = kMaxLogN - 1; j >= 0; --j) { if (R[j][s] < C) { jumps += (1 << j); s = R[j][s]; } } return C <= R[0][s] && R[0][s] <= D ? jumps + 1 : -1; }
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