이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
using namespace std;
using namespace __gnu_pbds;
using ll = long long;
using ii = pair<int, int>;
using vi = vector<int>;
#define pb push_back
#define pp pop_back
#define ff first
#define ss second
#define lb lower_bound
typedef tree<int, null_type, less<int>, rb_tree_tag,
tree_order_statistics_node_update> indexed_set;
int DP[200001][101][2], A[200001];
string solve_puzzle(string S, vector<int> C) {
int N = S.length(), K = C.size(); string res(N, '?');
DP[0][0][0] = 1; int P = 0;
for(int l = 1; l <= N; l++) {
if(S[l - 1] == '_') {
P = l;
for(int i = 0; i <= K; i++)
DP[l][i][0] = DP[l - 1][i][0];
continue;
}
if(S[l - 1] == '.') {
for(int i = 0; i <= K; i++)
DP[l][i][0] = DP[l - 1][i][0];
}
for(int i = 1; i <= K; i++) {
if(C[i - 1] <= l && P <= l - C[i - 1] && S[l - C[i - 1] - 1] != 'X')
DP[l][i][0] |= DP[max(0, l - C[i - 1] - 1)][i - 1][0];
}
}
P = N + 1;
DP[N + 1][K + 1][1] = 1;
for(int l = N; l >= 1; l--) {
if(S[l - 1] == '_') {
P = l;
for(int i = 1; i <= K + 1; i++)
DP[l][i][1] = DP[l + 1][i][1];
continue;
}
if(S[l - 1] == '.') {
for(int i = 1; i <= K + 1; i++)
DP[l][i][1] = DP[l + 1][i][1];
}
for(int i = 1; i <= K; i++) {
if(C[i - 1] + l - 1 <= N && P > C[i - 1] + l - 1 && S[l + C[i - 1] - 1] != 'X') {
DP[l][i][1] |= DP[min(N + 1, l + C[i - 1] + 1)][i + 1][1];
int U = DP[min(N + 1, l + C[i - 1] + 1)][i + 1][1];
int V = DP[max(0, l - 2)][i - 1][0];
if(U && V && S[l - 2] != 'X')
A[l]++, A[l + C[i - 1]]--;
}
}
}
for(int l = 1; l <= N; l++) {
if(S[l - 1] == '_') continue;
for(int i = 1; i <= K; i++) {
if(C[i - 1] + l - 1 <= N && P > C[i - 1] + l - 1 && S[l + C[i - 1] - 1] != 'X') {
int U = DP[min(N + 1, l + C[i - 1] + 1)][i + 1][1];
int V = DP[max(0, l - 2)][i - 1][0];
if(U && V && S[l - 2] != 'X')
A[l]++, A[l + C[i - 1]]--;
}
}
}
for(int l = 1; l <= N; l++) {
A[l] += A[l - 1];
if(S[l - 1] != '.') res[l - 1] = S[l - 1];
else {
if(!A[l]) res[l - 1] = '_';
else {
int ok = 0;
for(int i = 0; i <= K; i++)
ok |= DP[l - 1][i][0] & DP[l + 1][i + 1][1];
if(!ok) res[l - 1] = 'X';
else res[l - 1] = '?';
}
}
}
return res;
}
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