제출 #558491

#제출 시각아이디문제언어결과실행 시간메모리
558491savacskaSprinkler (JOI22_sprinkler)C++17
41 / 100
4054 ms94744 KiB
#include <bits/stdc++.h> #define pb push_back #define mp make_pair #define x first #define y second using namespace std; typedef long long ll; typedef long double ld; const int MAXD = 40; const int MAXN = 200000; int MOD = 0; vector <int> g[MAXN + 5]; int height[MAXN + 5], position[MAXN + 5], parent[MAXN + 5], start_height[MAXN + 5], rows[MAXN + 5]; pair <int, int> subtree[MAXD + 5][MAXN + 5]; int tree[4 * MAXN + 5]; int path[MAXN + 5], start[MAXN + 5]; void dfs(int v, int pr, int hei) { parent[v] = pr; height[v] = hei; position[v] = rows[hei]; rows[hei]++; int pos = -1; for (int i = 0; i < (int) g[v].size(); i++) if (g[v][i] == pr) pos = i; if (pos != -1) { swap(g[v][pos], g[v].back()); g[v].pop_back(); } for (int u : g[v]) dfs(u, v, hei + 1); return; } void dfsik(int v) { for (int u : g[v]) { dfsik(u); } subtree[0][v] = mp(position[v], position[v]); if (!g[v].empty()) { subtree[1][v] = mp(position[g[v][0]], position[g[v].back()]); int lef = 0, rig = (int) g[v].size() - 1; for (int i = 2; i <= MAXD; i++) { while (lef <= rig && subtree[i - 1][g[v][lef]] == mp(-1, -1)) lef++; while (lef <= rig && subtree[i - 1][g[v][rig]] == mp(-1, -1)) rig--; if (lef <= rig) subtree[i][v] = mp(subtree[i - 1][g[v][lef]].x, subtree[i - 1][g[v][rig]].y); else break; } } return; } int main() { //freopen("input.txt", "r", stdin); //freopen("output.txt", "w", stdout); ios_base::sync_with_stdio(0); cin.tie(0); int n, mod; cin >> n >> mod; MOD = mod; for (int i = 0; i <= MAXD; i++) for (int j = 1; j <= n; j++) subtree[i][j] = mp(-1, -1); for (int i = 1; i < n; i++) { int u, v; cin >> u >> v; g[u].pb(v), g[v].pb(u); } for (int i = 1; i <= n; i++) cin >> start_height[i]; dfs(1, -1, 0); { int h = 0; int sum = 0; while (rows[h] > 0) { start[h] = sum; sum += rows[h]; h++; } } for (int i = 1; i <= n; i++) position[i] += start[height[i]]; dfsik(1); int STEP = 1; while (STEP < n) STEP *= 2; for (int i = 1; i <= 2 * STEP - 1; i++) tree[i] = 1; int quer; cin >> quer; for (int rep = 1; rep <= quer; rep++) { int typ; cin >> typ; if (typ == 1) { int vert, dist, mn; cin >> vert >> dist >> mn; int tek = vert; int uk = 0; path[uk] = tek; uk++; for (int i = 1; i <= dist; i++) { if (parent[tek] == -1) break; tek = parent[tek]; path[uk] = tek; uk++; } for (int fin = height[vert] - dist; fin <= height[vert] + dist; fin++) { int x = (dist + height[vert] - fin) / 2; if (x >= uk) x = uk - 1; if (height[path[x]] > fin) continue; int y = fin - height[path[x]]; pair <int, int> bounds = subtree[y][path[x]]; if (bounds.x == -1) continue; int L = bounds.x + STEP, R = bounds.y + STEP; while (L <= R) { if (L % 2 == 1) { tree[L] = (ll) tree[L] * (ll) mn % (ll) MOD; L++; } if (R % 2 == 0) { tree[R] = (ll) tree[R] * (ll) mn % (ll) MOD; R--; } L /= 2, R /= 2; } } } else { int vert; cin >> vert; int pos = position[vert] + STEP; int ans = start_height[vert]; while (pos > 0) { ans = (ll) ans * (ll) tree[pos] % (ll) MOD; pos /= 2; } cout << ans << '\n'; } } return 0; }
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