Submission #557841

#	Time	Username	Problem	Language	Result	Execution time	Memory
557841		fatemetmhr	Plus Minus (BOI17_plusminus)	C++17	54 / 100	43 ms	9148 KiB

plusminus

#include <bits/stdc++.h>

using namespace std;

typedef long long ll;

#define pb     push_back
#define all(x) x.begin(), x.end()
#define fi     first
#define se     second

const int maxn5 = 2e3 + 10;
const int mod   = 1e9 + 7;

int a[maxn5][maxn5];

inline ll pw(ll a, ll b){
    ll ret = 1;
    for(int i = 0; i < b; i++)
        ret = ret * a % mod;
    return ret;
}

int main(){
    ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);

    int n, m, k; cin >> n >> m >> k;

    if(k == 0){
        return cout << (pw(2, n) + pw(2, m) + mod - 2) % mod << endl, 0;
    }

    for(int i = 0; i < k; i++){
        int x, y;
        char ty; cin >> ty >> x >> y;
        x--; y--;
        a[x][y] = (ty == '+' ? 2 : 1);
    }

    ll ans = 0;
    ll have = 1;
    for(int j = 0; j < m; j++){
        bool re = true;
        for(int i = 0; i < n; i++)
            re &= (a[i][j] == 0);
        if(re)
            have = have * 2 % mod;
        else{
            int v = -1;
            for(int i = 0; i < n; i++) if(a[i][j] != 0)
                v = i;
            for(int i = v; i < n; i += 2) if(a[i][j] != a[v][j] && a[i][j] != 0)
                have = 0;
            for(int i = v; i >= 0; i -= 2) if(a[i][j] != a[v][j] && a[i][j] != 0)
                have = 0;
            int val2 = (a[v][j] == 1 ? 2 : 1);
            for(int i = v - 1; i >= 0; i -= 2) if(a[i][j] != val2 && a[i][j] != 0)
                have = 0;
            for(int i = v + 1; i < n; i += 2) if(a[i][j] != val2 && a[i][j] != 0)
                have = 0;
        }
    }
    ans = have;

    //cout << "ok " << ans << endl;

    have = 1;
    for(int i = 0; i < n; i++){
        bool re = true;
        for(int j = 0; j < m; j++)
            re &= (a[i][j] == 0);
        if(re)
            have = have * 2 % mod;
        else{
            int v = -1;
            for(int j = 0; j < m; j++) if(a[i][j] != 0)
                v = j;
            for(int j = v; j < m; j += 2) if(a[i][j] != a[i][v] && a[i][j] != 0)
                have = 0;
            for(int j = v; j >= 0; j -= 2) if(a[i][j] != a[i][v] && a[i][j] != 0)
                have = 0;
            int val2 = (a[i][v] == 1 ? 2 : 1);
            for(int j = v - 1; j >= 0; j -= 2) if(a[i][j] != val2 && a[i][j] != 0)
                have = 0;
            for(int j = v + 1; j < m; j += 2) if(a[i][j] != val2 && a[i][j] != 0)
                have = 0;
        }
    }

    ans = (ans + have) % mod;

    //cout << ans << endl;

    bool re = true;
    for(int i = 0; i < n; i++) for(int j = 0; j < m; j++)
        re &= a[i][j] == 0 || (a[i][j] == ((i + j) % 2 == 0 ? 1 : 2));
    if(re)
        ans = (ans + mod - 1) % mod;
    re = true;
    for(int i = 0; i < n; i++) for(int j = 0; j < m; j++)
        re &= a[i][j] == 0 || (a[i][j] == ((i + j) % 2 == 0 ? 2 : 1));
    if(re)
        ans = (ans + mod - 1) % mod;
    cout << ans << endl;
}

• Subtask 1: 12 / 12
• Subtask 2: 42 / 42
• Subtask 3: 0 / 46