제출 #556890

#제출 시각아이디문제언어결과실행 시간메모리
556890DanShadersSightseeing in Kyoto (JOI22_kyoto)C++17
40 / 100
497 ms71016 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> using namespace std; namespace x = __gnu_pbds; template <typename T> using ordered_set = x::tree<T, x::null_type, less<T>, x::rb_tree_tag, x::tree_order_statistics_node_update>; template <typename T> using normal_queue = priority_queue<T, vector<T>, greater<>>; #define all(x) begin(x), end(x) #define sz(x) ((int) (x).size()) #define x first #define y second using ll = long long; using ld = long double; #define int ll const int N = 1e5 + 10, M = 2010, INF = 0x3f3f3f3f3f3f3f3f; int suff[N]; int eliminate(int *a, int n, pair<int, int> *b) { suff[n] = +INF; for (int i = n; i--; ) { suff[i] = min(suff[i + 1], a[i]); } int mn = +INF, m = 0; for (int i = 0; i < n; ++i) { if (mn <= a[i] && suff[i + 1] <= a[i]) { continue; } mn = min(mn, a[i]); b[m++] = {a[i], i}; } return m; } int a[N], b[N]; pair<int, int> c[M], d[M]; int dp[M][M]; signed main() { cin.tie(0)->sync_with_stdio(0); int n, m; cin >> n >> m; for (int i = 0; i < n; ++i) { cin >> a[i]; } for (int i = 0; i < m; ++i) { cin >> b[i]; } n = eliminate(a, n, c); m = eliminate(b, m, d); fill(dp[0], dp[M], +INF); dp[0][0] = 0; for (int i = 0; i < n; ++i) { for (int j = 0; j < m; ++j) { dp[i + 1][j] = min(dp[i + 1][j], dp[i][j] + d[j].x * (c[i + 1].y - c[i].y)); dp[i][j + 1] = min(dp[i][j + 1], dp[i][j] + c[i].x * (d[j + 1].y - d[j].y)); } } cout << dp[n - 1][m - 1]; }
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