답안 #55339

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
55339 2018-07-07T04:53:53 Z red1108 비밀 (JOI14_secret) C++17
컴파일 오류
0 ms 0 KB
#include "secret.h"
#include <stdio.h>
#include <algorithm>
#include <stdlib.h>
using namespace std;
int si=1,h=1;
int dp[20][2000];
int input[2000];
void fillup(int st,int l, int r)
{
    int mid, i;
    if(st>=9) return ;
    mid=(r+l-1)/2;
    for(i=mid;i>=l;i--)
    {
        if(i==mid) {dp[st][i]=input[i];continue;}
        dp[st][i]=secret(input[i],dp[st][i+1]);
    }
    mid=(r+l+1)/2;
    for(i=mid;i<=r;i++)
    {
        if(i==mid) {dp[st][i]=input[i];continue;}
        dp[st][i]=secret(dp[st][i-1],input[i]);
    }
    fillup(st+1, l, (l+r)/2);
    fillup(st+1, (l+r)/2+1, r);
}
void Init(int N, int A[])
{
    int i,j;
    while(si<N) {si*=2;h++;}
    for(i=N;i>=1;i--)
    {
        input[i]=A[i-1];
    }
    for(i=1;i<=h+1;i++)
    {
        for(j=1;j<=N*2;j++)
        {
            dp[i][j]=-1;
        }
    }
    fillup(1,1,si);
}
int secret(int x, int y)
{
    if(x==-1) return y;
    else if(y==-1) return x;
    return Secret(x, y);
}
int query(int x,int st,int l, int r, int s, int e)
{
    int mid;
    mid=(l+r)/2;
    if(l+r<s*2) return query(x*2+1,st+1,(l+r)/2+1, r, s, e);
    else if(l+r>e*2) return query(x*2,st+1, l, (l+r)/2, s, e);
    else
    {
        return secret(dp[st][s],dp[st][e]);
    }
}
int Query(int L, int R)
{
    L++;
    R++;
    if(L+1==R) return secret(input[L],input[R]);
    else if(L==R) return input[L];
    return query(1,1,1,si,L, R);
}

Compilation message

secret.cpp: In function 'void fillup(int, int, int)':
secret.cpp:17:19: error: 'secret' was not declared in this scope
         dp[st][i]=secret(input[i],dp[st][i+1]);
                   ^~~~~~
secret.cpp:17:19: note: suggested alternative: 'Secret'
         dp[st][i]=secret(input[i],dp[st][i+1]);
                   ^~~~~~
                   Secret
secret.cpp:23:19: error: 'secret' was not declared in this scope
         dp[st][i]=secret(dp[st][i-1],input[i]);
                   ^~~~~~
secret.cpp:23:19: note: suggested alternative: 'Secret'
         dp[st][i]=secret(dp[st][i-1],input[i]);
                   ^~~~~~
                   Secret