Submission #552347

#	Time	Username	Problem	Language	Result	Execution time	Memory
552347		pokmui9909	Krov (COCI17_krov)	C++17	112 / 140	1581 ms	14520 KiB

krov

#include <bits/stdc++.h>
using namespace std;
using ll = long long;
  
ll N;
ll A[100005];
ll B[100005];
ll C[100005];
struct BIT{
    ll T[300015] = {};
    void update(ll k, ll v){while(k <= 300010) T[k] += v, k += k & -k;}
    ll sum(ll k){ll r = 0;while(k >= 1) r += T[k], k -= k & -k; return r;}
    ll query(ll l, ll r) {return sum(r) - sum(l - 1);}
};
BIT pfs, pfc, sfs, sfc;
vector<ll> V;
const ll INF = 1e10;
ll Idx1(ll k){
    return lower_bound(V.begin(), V.end(), k) - V.begin();
}
ll Idx2(ll k){
    return upper_bound(V.begin(), V.end(), k) - V.begin() - 1;
}
  
ll f(ll X, ll K){
    ll r = 0;
    K -= X;
    r += K * pfc.query(Idx1(-INF), Idx2(K)) - pfs.query(Idx1(-INF), Idx2(K));
    r += pfs.query(Idx1(K + 1), Idx2(INF)) - K * pfc.query(Idx1(K + 1), Idx2(INF));
  
    K += 2 * X;
    r += K * sfc.query(Idx1(-INF), Idx2(K)) - sfs.query(Idx1(-INF), Idx2(K));
    r += sfs.query(Idx1(K + 1), Idx2(INF)) - K * sfc.query(Idx1(K + 1), Idx2(INF));
    return r;
}
  
int main(){
    cin.tie(0) -> sync_with_stdio(false);
  
    V.push_back(-INF - 1);
    V.push_back(-INF);
    V.push_back(INF);
    cin >> N;
    for(ll i = 1; i <= N; i++){
        cin >> A[i];
        B[i] = A[i] + i;
        C[i] = A[i] - i;
        V.push_back(A[i]); V.push_back(B[i]); V.push_back(C[i]);
    }
    sort(V.begin(), V.end());
    V.erase(unique(V.begin(), V.end()), V.end());
    ll ans = 1e18;
    for(ll i = 1; i <= N; i++){
        sfs.update(Idx1(B[i]), B[i]);
        sfc.update(Idx1(B[i]), 1);
    }
    for(ll i = 1; i <= N; i++){
        pfs.update(Idx1(C[i]), C[i]);
        pfc.update(Idx1(C[i]), 1);
        sfs.update(Idx1(B[i]), -B[i]);
        sfc.update(Idx1(B[i]), -1);
        ll L = 0, R = 2e9;
        while(R - L > 10){
            ll p = (L * 2 + R) / 3, q = (L + R * 2) / 3;
            if(f(i, p) <= f(i, q)) R = q;
            else L = p;
        }
        L = max(L, i);
        L = max(L, N + 1 - i);
        for(ll j = L; j <= R; j++){
            ans = min(ans, f(i, j));
        }
    }
    cout << ans;
}

• Subtask 1: 14 / 14
• Subtask 2: 14 / 14
• Subtask 3: 14 / 14
• Subtask 4: 14 / 14
• Subtask 5: 14 / 14
• Subtask 6: 14 / 14
• Subtask 7: 14 / 14
• Subtask 8: 14 / 14
• Subtask 9: 0 / 14
• Subtask 10: 0 / 14