제출 #551260

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
551260		AmShZ	열대 식물원 (Tropical Garden) (IOI11_garden)	C++11	100 / 100	2801 ms	71820 KiB

garden

//khodaya khodet komak kon
# include "gardenlib.h"
# include <bits/stdc++.h>

using namespace std;

typedef long long                                        ll;
typedef long double                                      ld;
typedef pair <int, int>                                  pii;
typedef pair <pii, int>                                  ppi;
typedef pair <int, pii>                                  pip;
typedef pair <pii, pii>                                  ppp;
typedef pair <ll, ll>                                    pll;

# define A                                               first
# define B                                               second
# define endl                                            '\n'
# define sep                                             ' '
# define all(x)                                          x.begin(), x.end()
# define kill(x)                                         return cout << x << endl, 0
# define SZ(x)                                           int(x.size())
# define lc                                              id << 1
# define rc                                              id << 1 | 1
# define fast_io                                         ios::sync_with_stdio(0);cin.tie(0); cout.tie(0);

ll power(ll a, ll b, ll md) {return (!b ? 1 : (b & 1 ? a * power(a * a % md, b / 2, md) % md : power(a * a % md, b / 2, md) % md));}

const int xn = 5e5 + 10;
const int xm = - 20 + 10;
const int sq = 320;
const int inf = 1e9 + 10;
const ll INF = 1e18 + 10;
const ld eps = 1e-15;
const int mod = 1e9 + 7;//998244353;
const int base = 257;

struct edge{
	int from, to, tabe;
};

int n, ptr, ans[xn], a[xn], q;
edge E[xn];
vector <int> adj[2][xn], g[xn], jad;
vector <pii> que[xn];
bool is_good[xn], mark[xn];
deque <int> dq;

void DFS(int v){
	dq.push_back(v);
	if (mark[v])
		return;
	mark[v] = true;
	DFS(E[v].tabe);
}
void DFS2(int v, int rt, int h = 0){
	jad.push_back(v);
	mark[v] = true;
	if (v == adj[0][E[v].from][0]){
		for (int i = 0; i < q; ++ i){
			int k = a[i];
			if (k < h)
				ans[i] += is_good[jad[h - k]];
			else{
				k -= h;
				k = (k + rt) % SZ(dq);
				ans[i] += is_good[dq[k]];
			}
		}
	}
	for (int u : g[v]){
		if (mark[u])
			continue;
		DFS2(u, rt, h + 1);
	}
	jad.pop_back();
}

void count_routes(int N, int M, int P, int R[][2], int Q, int G[]){
	//int N, M, P, Q;
	//cin >> N >> M >> P;
	n = N, q = Q;
	for (int i = 0; i < M; ++ i){
		int v, u;
		//cin >> v >> u;
		v = R[i][0], u = R[i][1];

		adj[0][v].push_back(ptr);
		adj[1][u].push_back(ptr);
		E[ptr].from = v;
		E[ptr].to = u;
		ptr ++;

		adj[0][u].push_back(ptr);
		adj[1][v].push_back(ptr);
		E[ptr].from = u;
		E[ptr].to = v;
		ptr ++;
	}
	for (int i = 0; i < n; ++ i)
		sort(all(adj[0][i]));
	for (int i = 0; i < ptr; ++ i){
		int v = E[i].to;
		if (adj[0][v][0] != (i ^ 1))
			E[i].tabe = adj[0][v][0];
		else if (1 < SZ(adj[0][v]))
			E[i].tabe = adj[0][v][1];
		else
			E[i].tabe = adj[0][v][0];
		g[E[i].tabe].push_back(i);
	}
	for (int u : adj[1][P])
		is_good[u] = true;
	//cin >> Q;
	for (int _ = 0; _ < Q; ++ _){
		int k = G[_];
		a[_] = k - 1;
		//cin >> k;
	}
	for (int i = 0; i < ptr; ++ i){
		if (mark[i])
			continue;
		dq.clear();
		DFS(i);
		while (dq.front() != dq.back())
			mark[dq.front()] = false, dq.pop_front();
		dq.pop_back();
		for (int j = 0; j < SZ(dq); ++ j){
			int v = dq[j];
			jad.clear();
			DFS2(v, j);
		}
	}
	for (int i = 0; i < Q; ++ i){
		//cout << ans[i] << endl;
		answer(ans[i]);
	}
}
/*
int main(){
	fast_io;

	count_routes();

	return 0;
}
*/
/*
5 5 2
1 0
1 2
3 2
1 3
4 2
2
3 1
*/

• Subtask 1: 49 / 49
• Subtask 2: 20 / 20
• Subtask 3: 31 / 31