이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define ll long long
#include "books.h"
using namespace std;
//
// --- Sample implementation for the task books ---
//
// To compile this program with the sample grader, place:
// books.h books_sample.cpp sample_grader.cpp
// in a single folder and run:
// g++ books_sample.cpp sample_grader.cpp
// in this folder.
//
ll val[100005], used[100005];
ll getval(int i)
{
if(val[i] == 0)
val[i] = skim(i);
return val[i];
}
void solve(int N, int K, long long A, int S)
{
vector<int> ans;
ll sum = 0;
for(int i = 1; i <= K; i++)
{
ans.emplace_back(i);
sum += getval(i);
used[i] = 1;
}
if(sum > 2 * A)
{
impossible();
return;
}
if(A <= sum)
{
answer(ans);
return;
}
for(int i = 1; i <= K; i++)
{
//cerr << "exchanging " << i << '\n';
int L = 1, R = N;
while(L < R)
{
int mid = (L + R + 1) / 2, m = -1;
if(used[mid])
{
R = mid - 1;
continue;
}
ll dif = 0;
for(int j = 0; j < K; j++)
if(getval(mid) - getval(ans[j]) + sum <= 2 * A)
if(getval(mid) - getval(ans[j]) > dif)
dif = getval(mid) - getval(ans[j]), m = j;
if(m >= 0) L = mid;
else R = mid - 1;
}
if(!used[L])
{
int m = -1;
ll dif = 0;
for(int j = 0; j < K; j++)
if(getval(L) - getval(ans[j]) + sum <= 2 * A)
if(getval(L) - getval(ans[j]) > dif)
dif = getval(L) - getval(ans[j]), m = j;
used[L] = 1;
sum += getval(L) - getval(ans[m]);
ans[m] = L;
}
else
{
impossible();
return;
}
if(A <= sum)
{
answer(ans);
return;
}
}
impossible();
}
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