제출 #550434

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
550434		elazarkoren	선물상자 (IOI15_boxes)	C++17	10 / 100	3 ms	212 KiB

boxes

#include <bits/stdc++.h>
#include "boxes.h"
#define x first
#define y second
#define all(v) v.begin(), v.end()
#define chkmin(a, b) a = min(a, b)
#define chkmax(a, b) a = max(a, b)
using namespace std;
typedef long long ll;
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef pair<int, int> pii;
typedef vector<pii> vii;

const int MAX_N = 1e6 + 5;
const ll infinity = 1e18;

ll dp[MAX_N];

ll Solve(vi &p, int l) {
    int n = p.size();
    ll ans = l;
    sort(all(p));
    for (int i = 0; i < n - 1; i++) {
        chkmin(ans, ll(2) * (p[i] + (l - p[i + 1])));
    }
    chkmin(ans, ll(2) * p[n - 1]);
    chkmin(ans, ll(2) * (l - p[0]));
    return ans;
}

int n, k, l;

ll Solve(int c, vi &p) {
    int ind = min(k * c, n);
    ll ans = 0;
    for (int i = 0; i < ind; i += k) {
        int r = min(i + k, n);
        ans += min<ll>(l, 2 * p[r - 1]);
    }
    for (int i = n - 1; i >= ind; i--) {
        int left = max(ind, i - k + 1);
        ans += min<ll>(l, 2 * (l - p[left]));
    }
    return ans;
}

long long delivery(int N, int K, int L, int P[]) {
    n = N, k = K, l = L;
    vi p(n);
    ll ans = infinity;
    for (int i = 0; i < n; i++) p[i] = P[i];
    for (int c = 0; k * (c - 1) < n; c++) {
        chkmin(ans, Solve(c, p));
    }
//    sort(p, p + n);
//    for (int i = 0; i < n; i++) {
//        vi curr;
//        dp[i] = infinity;
//        for (int j = i; j >= 0; j--) {
//            curr.push_back(p[j]);
//            if (curr.size() > k) break;
//            ll x = (j > 0 ? dp[j - 1] : 0);
//            chkmin(dp[i], x + Solve(curr, l));
//        }
//    }
//    chkmin(ans, dp[n - 1]);
    return ans;
}
//3 2 8
//1 2 5

컴파일 시 표준 에러 (stderr) 메시지

boxes.cpp: In function 'll Solve(vi&, int)':
boxes.cpp:21:19: warning: conversion from 'std::vector<int>::size_type' {aka 'long unsigned int'} to 'int' may change value [-Wconversion]
   21 |     int n = p.size();
      |             ~~~~~~^~

• Subtask 1: 10 / 10
• Subtask 2: 0 / 10
• Subtask 3: 0 / 15
• Subtask 4: 0 / 15
• Subtask 5: 0 / 20
• Subtask 6: 0 / 30