oj.uz

답안 #550388

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
550388 2022-04-18T02:11:00 Z farhan132 Pinball (JOI14_pinball) C++17
11 / 100
 1 ms 340 KB 
/***Farhan132***/
//#pragma GCC optimize("Ofast")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,avx2,fma")
//#pragma GCC optimization ("unroll-loops")
//#pragma GCC optimize("Ofast,fast-math")
 
 
#include <bits/stdc++.h>
 
 
 
using namespace std;
 
typedef long long ll;
typedef unsigned long long ull;
typedef double dd;
typedef vector<ll> vll;
typedef pair<ll , ll> ii;
typedef vector< ii > vii;
typedef pair < pair < ll , ll > , pair < ll , ll > > cm; 
typedef tuple < ll,  ll, ll > tp;
 
#define ff first
#define ss second
#define pb push_back
#define in insert
#define f0(b) for(int i=0;i<(b);i++)
#define f00(b) for(int j=0;j<(b);j++)
#define f1(b) for(int i=1;i<=(b);i++)
#define f11(b) for(int j=1;j<=(b);j++)
#define f2(a,b) for(int i=(a);i<=(b);i++)
#define f22(a,b) for(int j=(a);j<=(b);j++)
#define sf(a) scanf("%lld",&a)
#define sff(a,b) scanf("%lld %lld", &a , &b)
#define pf(a) printf("%lld\n",a)
#define pff(a,b) printf("%lld %lld\n", a , b)
#define bug printf("**!\n")
#define mem(a , b) memset(a, b ,sizeof(a))
#define front_zero(n) __builtin_clzll(n)
#define back_zero(n) __builtin_ctzll(n)
#define total_one(n) __builtin_popcount(n)
#define clean fflush(stdout)
 
const ll mod =  (ll) 998244353;
//const ll mod =  (ll) 1e9 + 7;
const ll maxn = (ll)1e8 + 5;
const int nnn = 1048590;
const int inf = numeric_limits<int>::max()-1;
//const ll INF = numeric_limits<ll>::max()-1;
const ll INF = (ll)1e18;
 
ll dx[]={0,1,0,-1};
ll dy[]={1,0,-1,0};
ll dxx[]={0,1,0,-1,1,1,-1,-1};
ll dyy[]={1,0,-1,0,1,-1,1,-1};
 
bool USACO = 0;
 
mt19937 rng(chrono::system_clock::now().time_since_epoch().count());
 
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
 
template <typename T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;

const ll N = 4e5 + 5;

ll a[N] , b[N] , c[N] , d[N];
struct seg_tree{

  struct typo{
    ll mn;
    void setup(ll v){
      mn = v;
    }
  };

  vector < typo > b;
  ll n;

  void init(ll l, ll r, ll node){
    b[node].setup(INF);
    return;
  }

  typo merge(typo a, typo b){
    typo c;
    c.mn = min(a.mn, b.mn);
    return c;
  }

  void build(ll l, ll r, ll node){
    if(l == r){
      init(l,r,node);
      return;
    }
    ll mid = (l + r)/2;
    ll n1 = 2*node;
    ll n2 = n1 + 1;
    build(l, mid , n1);
    build(mid+1, r, n2);
    b[node] = merge(b[n1] , b[n2]);
    return;
  }

  void build(ll _n){
    n = _n;
    b.resize(4*n);
    build(1,n,1); // optional
  }

  void up(ll l, ll r, ll node, ll x, ll y, ll v){
    if(y < l || x > r) return;
    if(x <= l && y >= r){
      b[node].mn = min(b[node].mn, v);
      return;
    }
    ll mid = (l + r)/2;
    ll n1 = 2*node;
    ll n2 = n1 + 1;
    up(l , mid , n1 , x , y , v);
    up(mid + 1, r, n2, x, y , v);
    b[node] = merge(b[n1] , b[n2]);
    return;
  }

  void up(ll x, ll v){
    up(1,n,1,x,x,v);
    return;
  }
  
  typo get(ll l, ll r, ll node, ll x, ll y){
    if(y < l || x > r) return {INF};
    if(x <= l && y >= r){
      return b[node];
    }
    ll mid = (l + r)/2;
    ll n1 = 2*node;
    ll n2 = n1 + 1;
    return merge(get(l , mid , n1 , x , y) , get(mid + 1, r , n2 , x , y));
  }

  ll get(ll l, ll r){
    return get(1,n,1,l,r).mn;
  }

  /* Final Check!!!
     1. Typo, Okay?
     2. Init Okay? (Build!!)
     3. Merge, Okay?
     4. Lazy Needed ? YES | NO (if NO, REMOVE anything related to lazy prop)
     5. Dummy?
     6. Check Update, Get, etc function's Merge, Lazy Prop , Init :D
     7, Even after a WA, check for possible Out Of Bound/MLE/RE cases
  */

}pref, suf;



void solve(){
  
  ll n , m;
  cin >> m >> n;

  vector < ll > idx;
  idx.pb(1); idx.pb(n);

  for(ll i = 1; i <= m; i++){
    cin >> a[i] >> b[i] >> c[i] >> d[i];
    idx.pb(a[i]) , idx.pb(b[i]) , idx.pb(c[i]);
  }
  sort(idx.begin(), idx.end());
  idx.erase(unique(idx.begin(), idx.end()), idx.end());
  n = idx.size();

  pref.build(n);
  suf.build(n);
  ll ans = INF;
  for(ll i = 1; i <= m; i++){
    a[i] = lower_bound(idx.begin(), idx.end(), a[i]) - idx.begin() + 1;
    b[i] = lower_bound(idx.begin(), idx.end(), b[i]) - idx.begin() + 1;
    c[i] = lower_bound(idx.begin(), idx.end(), c[i]) - idx.begin() + 1;
    ll x = INF, y = INF;
    if(a[i] == 1) x = 0;
    if(b[i] == n) y = 0;
    x = min(x, pref.get(a[i], c[i]));
    y = min(y, suf.get(c[i], b[i]));
    ans = min(ans, x + y + d[i]);
    pref.up(c[i], d[i] + x);
    suf.up(c[i], d[i] + y);
  }
  if(ans == INF) ans = -1;
  cout << ans << '\n';


  return;
}
 
int main() {
    
    
    #ifdef LOCAL
        freopen("in", "r", stdin);
        freopen("out", "w", stdout);
        auto start_time = clock();
    #else 
       ios_base::sync_with_stdio(0); cin.tie(NULL); cout.tie(NULL);
    #endif
 
    //pre(N);
 
    ll T = 1, CT = 0;  //cin >> T; 
 
    while(T--){
       //  cout << "Case #" << ++CT <<": " ;
        solve();
    }
    #ifdef LOCAL
        auto end_time = clock();
        cerr<< "Execution time: "<<(end_time - start_time)*(int)1e3/CLOCKS_PER_SEC<<" ms\n";
    #endif
 
    return 0;
}

Compilation message

pinball.cpp: In function 'int main()':
pinball.cpp:214:15: warning: unused variable 'CT' [-Wunused-variable]
  214 |     ll T = 1, CT = 0;  //cin >> T;
      |               ^~

Subtask #1
11.0 / 11.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 340 KB Output is correct
2 Correct 1 ms 340 KB Output is correct
3 Correct 1 ms 340 KB Output is correct
4 Correct 1 ms 340 KB Output is correct
5 Correct 1 ms 340 KB Output is correct
6 Correct 1 ms 340 KB Output is correct
7 Correct 1 ms 340 KB Output is correct
8 Correct 1 ms 340 KB Output is correct

Subtask #2
0 / 18.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 340 KB Output is correct
2 Correct 1 ms 340 KB Output is correct
3 Correct 1 ms 340 KB Output is correct
4 Correct 1 ms 340 KB Output is correct
5 Correct 1 ms 340 KB Output is correct
6 Correct 1 ms 340 KB Output is correct
7 Correct 1 ms 340 KB Output is correct
8 Correct 1 ms 340 KB Output is correct
9 Correct 1 ms 340 KB Output is correct
10 Correct 1 ms 340 KB Output is correct
11 Incorrect 1 ms 340 KB Output isn't correct
12 Halted 0 ms 0 KB -

Subtask #3
0 / 22.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 340 KB Output is correct
2 Correct 1 ms 340 KB Output is correct
3 Correct 1 ms 340 KB Output is correct
4 Correct 1 ms 340 KB Output is correct
5 Correct 1 ms 340 KB Output is correct
6 Correct 1 ms 340 KB Output is correct
7 Correct 1 ms 340 KB Output is correct
8 Correct 1 ms 340 KB Output is correct
9 Correct 1 ms 340 KB Output is correct
10 Correct 1 ms 340 KB Output is correct
11 Incorrect 1 ms 340 KB Output isn't correct
12 Halted 0 ms 0 KB -

Subtask #4
0 / 49.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 340 KB Output is correct
2 Correct 1 ms 340 KB Output is correct
3 Correct 1 ms 340 KB Output is correct
4 Correct 1 ms 340 KB Output is correct
5 Correct 1 ms 340 KB Output is correct
6 Correct 1 ms 340 KB Output is correct
7 Correct 1 ms 340 KB Output is correct
8 Correct 1 ms 340 KB Output is correct
9 Correct 1 ms 340 KB Output is correct
10 Correct 1 ms 340 KB Output is correct
11 Incorrect 1 ms 340 KB Output isn't correct
12 Halted 0 ms 0 KB -