oj.uz

답안 #549702

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
549702 2022-04-16T10:49:35 Z yoavL Boat (APIO16_boat) C++14
9 / 100
 3 ms 468 KB 
#include <iostream>
#include <vector>
#include <algorithm>
#include <string>
#include <set>
#include <unordered_set>
#include <map>
#include <unordered_map>
#include <queue>
#include <stack>
#include <bitset>
#include <math.h>
#include <fstream>
#include <iomanip>
#include <functional>
#include <numeric>
#include <chrono>
#include <random>

using namespace std;

using ll = long long;
using ld = long double;
using vll = vector<ll>;
using vvll = vector<vll>;
using vvvll = vector<vvll>;
using vvvvll = vector<vvvll>;
using vb = vector<bool>;
using vvb = vector<vb>;
using vvvb = vector<vvb>;
using vld = vector<ld>;
using vvld = vector<vld>;
using vstr = vector<string>;
using pll = pair<ll, ll>;
using vpll = vector<pll>;
using vvpll = vector<vpll>;
using pb = pair<bool, bool>;
using vpb = vector<pb>;
using vvpb = vector<vpb>;
using vi = vector<int>;
using vvi = vector<vi>;
using pi = pair<int, int>;
using vpi = vector<pi>;

const ll inf = (ll)5e9;
const ll mod = (ll)(1e9 + 7);

#define FAST        ios_base::sync_with_stdio(0)
#define FASTIN		cin.tie(0)
#define FASTOUT		cout.tie(0)

#define upmin(a, b) (a) = min((a), (b))
#define upmax(a, b) (a) = max((a), (b))

#define pr(x) cout << x << endl
#define prv(v) for(auto it : v) cout << it << " "; cout << endl;
#define prvv(v) for(auto it : v) { for(auto it2 : it) cout << it2 << " "; cout << endl; } cout << endl;
#define spr(x) cout << x << " "

//#define DBG_FLAG (1) // toggle to switch between bebug mode and solution mode
#ifdef DBG_FLAG
#define wpr(x) cout << #x << " = " << (x) << endl;
#define wprv(v) cout << #v << ": " << endl; for(auto it : v) cout << it << " "; cout << endl;
#define wprvv(v) cout << #v << ": " << endl; for(auto it : v) { for(auto it2 : it) cout << it2 << " "; cout << endl; } cout << endl;
#define wspr(x) cout << #x << ": " << x << " "
#endif

#ifndef DBG_FLAG
#define wpr(x)
#define wprv(v)
#define wprvv(v)
#define wspr(x)
#endif

#define rep(i, s, e) for(ll i = s; i < e; i++)
#define all(x) (x).begin(), (x).end()
#define pb push_back

const ll maxV = 1e6;


/*

Solution:

We've seen a slow solution so far:
We start with: [1, 0, 0, 0, ...]
And then each time we increase the current segment with all the values smaller than it.
If we make point compression, we'll get disinct segments. Shouldn't be too complicated.

*/


ll n;
vll a, b;
//vll dp;
//map<ll, ll> dp;
vll v;
void solve()
{
	cin >> n;
	a.resize(n), b.resize(n), v.resize(3 * n);
	rep(i, 0, n) {
		cin >> a[i] >> b[i];
		v[3 * i] = a[i], v[3 * i + 1] = b[i], v[3*i + 2] = b[i] + 1;
	}
	v.push_back(0);
	v.push_back(1);
	v.push_back(inf);
	sort(v.begin(), v.end());
	v.erase(unique(v.begin(), v.end()), v.end());
	wprv(v);
	rep(i, 0, n) {
		a[i] = lower_bound(v.begin(), v.end(), a[i]) - v.begin();
		b[i] = lower_bound(v.begin(), v.end(), b[i]) - v.begin();
	}
	wprv(a); wprv(b);
	vll dp(v.size(), 0);
	dp[0] = 1;
	wprv(dp);
	rep(i, 0, n) {
		ll sum = 0;
		rep(j, 0, a[i]) {
			sum += (dp[j] * (v[j+1] - v[j])) % mod;
			sum %= mod;
		}
 		wpr(sum);
		rep(j, a[i], b[i] + 1) {
			wpr(j);
			ll add = dp[j] * (v[j+1] - v[j]);
			dp[j] = (dp[j] + sum) % mod;
			sum += add;
			sum %= mod;
		}
		wprv(dp);
	}
	ll ans = 0;
	
	rep(i, 0, dp.size()-(ll)1) {
		ans = (ans + dp[i] * (v[i+1] - v[i])) % mod;
	}
	
	/*
	for (const auto& it : dp) {
		ans = (ans + it.second) % mod;
	}
	*/
	ans = (ans - 1 + mod) % mod;
	pr(ans);
}


int main()
{
	FAST;
	FASTIN; FASTOUT;
	solve();
}


/*

2
1 2
2 3

2
1 5
4 9



2
2 2
2 2
// 2


*/

Compilation message

boat.cpp: In function 'void solve()':
boat.cpp:76:38: warning: comparison of integer expressions of different signedness: 'll' {aka 'long long int'} and 'long long unsigned int' [-Wsign-compare]
   76 | #define rep(i, s, e) for(ll i = s; i < e; i++)
......
  140 |  rep(i, 0, dp.size()-(ll)1) {
      |      ~~~~~~~~~~~~~~~~~~~~~            
boat.cpp:140:2: note: in expansion of macro 'rep'
  140 |  rep(i, 0, dp.size()-(ll)1) {
      |  ^~~

Subtask #1
9.0 / 9.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 340 KB Output is correct
2 Correct 2 ms 340 KB Output is correct
3 Correct 2 ms 340 KB Output is correct
4 Correct 2 ms 340 KB Output is correct
5 Correct 2 ms 340 KB Output is correct
6 Correct 2 ms 340 KB Output is correct
7 Correct 2 ms 340 KB Output is correct
8 Correct 2 ms 340 KB Output is correct
9 Correct 2 ms 340 KB Output is correct
10 Correct 2 ms 340 KB Output is correct
11 Correct 1 ms 340 KB Output is correct
12 Correct 2 ms 340 KB Output is correct
13 Correct 2 ms 468 KB Output is correct
14 Correct 2 ms 340 KB Output is correct
15 Correct 1 ms 340 KB Output is correct
16 Correct 1 ms 340 KB Output is correct
17 Correct 1 ms 340 KB Output is correct
18 Correct 1 ms 340 KB Output is correct
19 Correct 1 ms 340 KB Output is correct
20 Correct 1 ms 340 KB Output is correct

Subtask #2
0 / 22.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 340 KB Output is correct
2 Correct 2 ms 340 KB Output is correct
3 Correct 2 ms 340 KB Output is correct
4 Correct 2 ms 340 KB Output is correct
5 Correct 2 ms 340 KB Output is correct
6 Correct 2 ms 340 KB Output is correct
7 Correct 2 ms 340 KB Output is correct
8 Correct 2 ms 340 KB Output is correct
9 Correct 2 ms 340 KB Output is correct
10 Correct 2 ms 340 KB Output is correct
11 Correct 1 ms 340 KB Output is correct
12 Correct 2 ms 340 KB Output is correct
13 Correct 2 ms 468 KB Output is correct
14 Correct 2 ms 340 KB Output is correct
15 Correct 1 ms 340 KB Output is correct
16 Correct 1 ms 340 KB Output is correct
17 Correct 1 ms 340 KB Output is correct
18 Correct 1 ms 340 KB Output is correct
19 Correct 1 ms 340 KB Output is correct
20 Correct 1 ms 340 KB Output is correct
21 Incorrect 3 ms 340 KB Output isn't correct
22 Halted 0 ms 0 KB -

Subtask #3
0 / 27.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 1 ms 212 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #4
0 / 42.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 340 KB Output is correct
2 Correct 2 ms 340 KB Output is correct
3 Correct 2 ms 340 KB Output is correct
4 Correct 2 ms 340 KB Output is correct
5 Correct 2 ms 340 KB Output is correct
6 Correct 2 ms 340 KB Output is correct
7 Correct 2 ms 340 KB Output is correct
8 Correct 2 ms 340 KB Output is correct
9 Correct 2 ms 340 KB Output is correct
10 Correct 2 ms 340 KB Output is correct
11 Correct 1 ms 340 KB Output is correct
12 Correct 2 ms 340 KB Output is correct
13 Correct 2 ms 468 KB Output is correct
14 Correct 2 ms 340 KB Output is correct
15 Correct 1 ms 340 KB Output is correct
16 Correct 1 ms 340 KB Output is correct
17 Correct 1 ms 340 KB Output is correct
18 Correct 1 ms 340 KB Output is correct
19 Correct 1 ms 340 KB Output is correct
20 Correct 1 ms 340 KB Output is correct
21 Incorrect 3 ms 340 KB Output isn't correct
22 Halted 0 ms 0 KB -