Submission #549586

#	Time	Username	Problem	Language	Result	Execution time	Memory
549586		Theo830	Keys (IOI21_keys)	C++17	9 / 100	107 ms	31760 KiB

keys

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const ll INF = 1e9+7;
const ll MOD = 998244353;
typedef pair<ll,ll> ii;
#define iii pair<ll,ii>
#define f(i,a,b) for(ll i = a;i < b;i++)
#define pb push_back
#define vll vector<ll>
#define F first
#define S second
#define all(x) (x).begin(), (x).end()
///I hope I will get uprating and don't make mistakes
///I will never stop programming
///sqrt(-1) Love C++
///Please don't hack me
///@TheofanisOrfanou Theo830
///Think different approaches (bs,dp,greedy,graphs,shortest paths,mst)
///Stay Calm
///Look for special cases
///Beware of overflow and array bounds
///Think the problem backwards
///Training
vector<ii>exo[20005];
bool v[20005]; ///keys
ll p[20005];
ll siz[20005];
ll find_par(ll a){
    if(p[a] == a){
        return a;
    }
    return p[a] = find_par(p[a]);
}
void enose(ll a,ll b){
    ll p1 = find_par(a);
    ll p2 = find_par(b);
    if(p1 != p2){
        p[p1] = p2;
        siz[p2] += siz[p1];
        siz[p1] = 0;
    }
}
std::vector<int> find_reachable(std::vector<int> r, std::vector<int> u, std::vector<int> v, std::vector<int> c) {
	std::vector<int> ans(r.size(), 1);
	ll n = r.size();
	ll m = u.size();
	f(i,0,m){
        exo[c[i]].pb(ii(u[i],v[i]));
	}
	ll timi[n];
	ll mini = n + 100;
	f(i,0,n){
        f(j,0,n){
            v[j] = 0;
            p[j] = j;
            siz[j] = 1;
        }
        queue<ll>q;
        v[r[i]] = 1;
        q.push(r[i]);
        while(!q.empty()){
            ll f = q.front();
            q.pop();
            for(auto x:exo[f]){
                enose(x.F,x.S);
                if(!v[r[x.F]]){
                    v[r[x.F]] = 1;
                    q.push(r[x.F]);
                }
                if(!v[r[x.S]]){
                    v[r[x.S]] = 1;
                    q.push(r[x.S]);
                }
            }
        }
        timi[i] = siz[find_par(i)];
        mini = min(mini,timi[i]);
	}
    f(i,0,n){
        if(timi[i] != mini){
            ans[i] = 0;
        }
	}
	return ans;
}

• Subtask 1: 9 / 9
• Subtask 2: 0 / 11
• Subtask 3: 0 / 17
• Subtask 4: 0 / 30
• Subtask 5: 0 / 33