제출 #54917

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
54917		kdh9949	Pipes (CEOI15_pipes)	C++17	30 / 100	3169 ms	14132 KiB

pipes

#include <bits/stdc++.h>
using namespace std;

const int N = 100001, H = 17;

int n, m, p[N], c[N], v[N], w[N], d[N], s[N][17], q[N];
vector<int> e[N];

int f(int x){ return p[x] = (x == p[x] ? x : f(p[x])); }

int g(int x, int y, int z){
    if(z) c[x] = 1;
    for(int i : e[x]) if(i != y) v[x] += g(i, x, z);
    v[x] += w[x]; w[x] = 0;
    if(y && z && !v[x]) printf("%d %d\n", x, y);
    return v[x];
}

void h(int x, int y, int z){
    s[x][0] = y;
    for(int i = 1; i < H; i++) s[x][i] = s[s[x][i - 1]][i - 1];
    for(int i : e[x]) if(i != y) h(i, x, z + 1);
}

int a(int x, int y){
    if(d[x] < d[y]) swap(x, y);
    for(int i = H - 1; i >= 0; i--) if(d[x] - (1 << i) >= d[y]) x = s[x][i];
    if(x == y) return x;
    for(int i = H - 1; i >= 0; i--) if(s[x][i] != s[y][i]){
        x = s[x][i]; y = s[y][i];
    }
    return s[x][0];
}

int main(){
    scanf("%d%d", &n, &m);
    iota(p, p + n + 1, 0);
    fill(c + 1, c + n + 1, 1);
    for(int x, y; m--; ){
        scanf("%d%d", &x, &y);
        if(f(x) != f(y)){
            if(c[f(x)] < c[f(y)]) swap(x, y);
            g(f(y), 0, 0);
            e[x].push_back(y); e[y].push_back(x);
            h(y, x, d[x] + 1);
            c[f(x)] += c[f(y)]; p[f(y)] = f(x);
        }
        else{ w[x]++; w[y]++; w[a(x, y)] -= 2; }
    }
    fill(c + 1, c + n + 1, 0);
    for(int i = 1; i <= n; i++) if(!c[i]) g(i, 0, 1);
}

컴파일 시 표준 에러 (stderr) 메시지

pipes.cpp: In function 'int main()':
pipes.cpp:36:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     scanf("%d%d", &n, &m);
     ~~~~~^~~~~~~~~~~~~~~~
pipes.cpp:40:14: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
         scanf("%d%d", &x, &y);
         ~~~~~^~~~~~~~~~~~~~~~

• Subtask 1: 0 / 10
• Subtask 2: 0 / 10
• Subtask 3: 0 / 10
• Subtask 4: 0 / 10
• Subtask 5: 10 / 10
• Subtask 6: 0 / 10
• Subtask 7: 10 / 10
• Subtask 8: 0 / 10
• Subtask 9: 0 / 10
• Subtask 10: 10 / 10