제출 #545714

#제출 시각아이디문제언어결과실행 시간메모리
545714balbitShuffle (NOI19_shuffle)C++14
85.01 / 100
16 ms24144 KiB
#include "shuffle.h" #include <bits/stdc++.h> //#define int ll using namespace std; #define ll long long #define f first #define s second #define pii pair<int, int> #define MX(a,b) a=max(a,b) #define MN(a,b) a=min(a,b) #define SZ(x) (int)(x).size() #define ALL(x) (x).begin(), (x).end() #define REP(i,n) for (int i = 0; i<n; ++i) #define REP1(i,n) for (int i = 1; i<=n; ++i) #define pb push_back #ifdef BALBIT #define bug(...) cerr<<"#"<<__LINE__<<": "<<#__VA_ARGS__<<"- ", _do(__VA_ARGS__) template<typename T> void _do( T && x) {cerr<<x<<endl;} template<typename T, typename ...S> void _do( T && x, S && ...y) {cerr<<x<<", "; _do(y...);} #else #define bug(...) #define endl '\n' #endif // BALBIT const int maxn = 1e3+5; #define VI vector<int> #ifdef BALBIT vector<int> per = {4,3,8,6,1,7,2,5}; std::vector< std::vector<int> > shuffle(std::vector< std::vector<int> > x){ REP(i, SZ(x)) { for (int &y:x[i]) { y = per[y-1]; } random_shuffle(ALL(x[i])); } random_shuffle(ALL(x)); return x; // REP(i, SZ(x)) { // for (int y : x[i]) cout<<y<<' '; // cout<<endl; // } // cout<<endl; // bug("enter!"); // vector<vector<int> > re(SZ(x), vector<int> (SZ(x[0]))); // REP(i, SZ(x)) REP(j, SZ(x[0])) cin>>x[i][j]; // return re; } #endif // BALBIT vector<vector<int> > myshuffle(vector<vector<int> > b) { for (auto &y : b) for (int &x : y) ++x; vector<vector<int> > gt = shuffle(b); for (auto &y : gt) { for(int &x : y) --x; sort(ALL(y)); } return gt; } vector<int> g[maxn]; // the induced graph from the buckets bool seen[maxn]; vector<int> ord2; void dfs2(int v) { seen[v] =1; ord2.pb(v); for (int u : g[v]) { if (!seen[u]) { dfs2(u); } } } vector<vector<int> > cleanshuffle(vector<vector<int> > ask, int N, int B, int K) { vector<vector<int> > gt = myshuffle(ask); vector<int> color(N); // which bucket is this number in in the original REP(i, B) { for (int x : gt[i]) color[x] = i; } // now time to make a loop vector<vector<int> > ask2 = ask; REP(i, B) { ask2[i][0] = ask[(i-1+B)%B][0]; } vector<vector<int> > gt2 = myshuffle(ask2); // ok now i can find the chain REP(i,B) { g[i].clear(); } REP(i, B) { // the type that appears the least number of times is the poker map<int, int> mp; for (int t : gt2[i]) { mp[color[t]]++; } assert(SZ(mp) == 2); vector<int> here; for (pii p :mp) { here.pb(p.f); } for (pii p : mp) { if (p.s == 1) { // found you int oth = here[0] ^ here[1] ^ p.f; g[p.f].pb(oth); // Color edge corresponds to index(i) -> index(i+1) } } } // now i just need to find the node of index 0 memset(seen, 0, sizeof seen); vector<vector<int> > ask3 = ask; swap(ask3[0][0], ask3[1][0]); swap(ask3[0][1], ask3[2][0]); // now 2 of index 0s are scattered in other zones, so wee look for the color with 2 scattered locations // (should be unique) vector<vector<int> > gt3 = myshuffle(ask3); map<int, int> funny; REP(i, B) { // the type that appears the least number of times is the poker map<int, int> mp; for (int t : gt3[i]) { mp[color[t]]++; } vector<int> here; int mostfreq = 0; for (pii p :mp) { MX(mostfreq, p.s); } for (pii p : mp) { if (p.s != mostfreq) { funny[p.f]++; } } } int one = -1; for (pii p:funny) { if (p.s == 2) { assert(one == -1); one = p.f; } } assert(one != -1); ord2.clear(); dfs2(one); vector<vector<int> > ret; for (int x : ord2) { ret.pb(gt[x]); } return ret; } int ONE = -1; vector<vector<int> > clean2(vector<vector<int> > ask, int N, int B, int K) { vector<vector<int> > gt= myshuffle(ask); if (ONE == -1) { // gotta find the one!!! vector<int> col(N); REP(i, B) { for (int x : gt[i]) col[x] = i; } vector<int> weird; assert(ask[0][0] == 0); swap(ask[0][0], ask[1][0]); vector<vector<int> > gt2 = myshuffle(ask); swap(ask[0][0], ask[1][0]); swap(ask[0][0], ask[1][1]); vector<vector<int> > gt3 = myshuffle(ask); swap(ask[0][0], ask[1][1]); for (auto V : {gt2, gt3}) { REP(i, B) { map<int, int> frq; for (int x : V[i]) { frq[col[x]]++; } // int badcol = frq[0]==1?0:1; for (int x : V[i]) { if (frq[col[x]] ==1) { weird.pb(x); } } } } bug(SZ(weird)); assert(SZ(weird) == 4); // one guy should appear twice REP(i, SZ(weird)) { REP(j,i) { if (weird[i] == weird[j]) { ONE = weird[i]; goto done; } } } done:; } bool in0 = 0; for (int x : ask[0]) if (x == 0) in0 = 1; bool onein0 = 0; for (int x : gt[0]) if (x == ONE) onein0 = 1; if (in0 != onein0) swap(gt[0], gt[1]); return gt; } vector<int> g1[maxn], g2[maxn]; vector<int> ord; void dfs(int v, bool one) { ord.pb(v); seen[v] = 1; for (int u : (one?g1:g2)[v]) { if (!seen[u]) { dfs(u, one^1); } } } #define vvi vector<vector<int> > vector<int> chg(vvi a, vvi b) { vector<int> GP(SZ(a) * SZ(a[0])); REP(i, SZ(a)) { for (int x : a[i]) { GP[x] = i; } } vector<int> re; REP(i, SZ(b)) { for (int x : b[i]) { if (i != GP[x]) { re.pb(x); } } } return re; } void ASS(bool t) { if (!t) { while(1); } } vector<int> run(int N, int B, int K, int Q, int isclean){ // shuffle solving for the case where the buckets AREN't shuffled auto F = [&](int &at) {int oat = at; at = (at+1)%B; return oat; }; vector<pair<VI, VI> > v; vector<int> strt; REP(i,N) strt.pb(i); v.pb({strt, strt}); // groups of {index, p[i]} while (1) { vector<vector<int> > ask (B); vector<int> whichbucket(N); // which bucket is this index tossed into? vector<int> group(N); // which group is this result from? bool need = 0; int AT = 0; int grp = 0; vector<vector<pair<VI, VI> > > yeah(SZ(v)); for (auto &e : v) { yeah[grp].resize(B); if (SZ(e.f) > 1) need = 1; REP(i, SZ(e.f)) { whichbucket[e.f[i]] = AT; yeah[grp][AT].f.pb(e.f[i]); ask[AT].pb(e.f[i]); F(AT); } for (int x : e.s) { group[x]=grp; } ++grp; } if (need == 0) break; vector<vector<int> > get; if (isclean == 1) get = myshuffle(ask); else if (isclean == 0) get = cleanshuffle(ask,N,B,K); else get = clean2(ask,N,B,K); vector<pair<VI, VI> > nv; REP(i, B) { REP(j, K) { yeah[group[get[i][j]]][i].s.pb( get[i][j]); } } for (auto & e : yeah) { REP(i,B) { if (SZ(e[i].f)) { nv.pb(e[i]); } } } v.swap(nv); } vector<int> re(N); bug(SZ(v)); assert(SZ(v) == N); REP(i, SZ(v)) { re[v[i].f[0]] = v[i].s[0] + 1; } return re; } vector<int> solve(int N, int B, int K, int Q, int ST) { if (ST == 3 || ST == 1) { return run(N,B,K,Q,1); } else if (ST == 4 || ST == 2) { assert(K == 2); vector<vector<int> > ask1, ask2; REP(i,N) { if (i % 2 == 0) { ask1.pb({i, i+1}); }else{ ask2.pb({i, (i+1)%N}); } } vector<vector<int> > gt1 = myshuffle(ask1), gt2 = myshuffle(ask2); sort(ALL(gt1)); sort(ALL(gt2)); // build graphs REP(i,SZ(gt1)) { g1[gt1[i][0]].pb(gt1[i][1]); g1[gt1[i][1]].pb(gt1[i][0]); g2[gt2[i][0]].pb(gt2[i][1]); g2[gt2[i][1]].pb(gt2[i][0]); } swap(ask1[0][0], ask1[1][0]); // swapping 0 and 2 (1 and 3 in 1-based) vector<vector<int> > c1 = myshuffle(ask1); swap(ask1[0][0], ask1[1][0]); // now look for the pair that doesn't appear in either ask1 or ask2: that is the sus pair vector<int> d1; for (vector<int> t : c1) { if (!binary_search(ALL(gt1), t) && !binary_search(ALL(gt2), t)) { bug(t[0], t[1]); assert(SZ(d1) == 0); d1 = t; } } swap(ask1[0][0], ask1[2][1]); vector<vector<int> > c2 = myshuffle(ask1); swap(ask1[0][0], ask1[2][1]); vector<int> d2; for (vector<int> t : c2) { if (!binary_search(ALL(gt1), t) && !binary_search(ALL(gt2), t)) { // assert(SZ(d2) == 0); // d2 = t; for (int y : t) d2.pb(y); } } bug(SZ(d1), SZ(d2)); ASS(SZ(d1) == 2); // ASS(SZ(d2) == 2); int one = -1; for (int x : d1) for (int y : d2) if (x == y) one = x; ASS(one != -1); dfs(one, 1); for (int &x : ord) ++x; return ord; } else if (ST == 6) { // try to steal 3 but with weird voodoo to unrandomize the buckets return run(N,B,K,Q,0); }else if (ST == 5) { // fucking hell return run(N,B,K,Q,2); } } #ifdef BALBIT signed main(){ ios::sync_with_stdio(0), cin.tie(0); bug(1,2); vector<int> gt = solve(8,2,4,-1,5); for(int x : gt) cout<<x<<' '; cout<<endl; } #endif

컴파일 시 표준 에러 (stderr) 메시지

shuffle.cpp: In function 'std::vector<int> solve(int, int, int, int, int)':
shuffle.cpp:410:1: warning: control reaches end of non-void function [-Wreturn-type]
  410 | }
      | ^
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