이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define f first
#define s second
#define m_p make_pair
#define all(x) (x).begin(),(x).end()
#define rall(x) (x).rbegin(),(x).rend()
#define vec vector
#define pb push_back
#define sz(x) (int)(x).size()
#define pw(x) (1LL<<(x))
#define fast_resp ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);
using namespace std;
typedef long long ll;
typedef pair<int,int> pii;
typedef long double ld;
typedef pair<int,ll> pil;
template<class T> bool umin(T &a,const T &b){return (a>b?a=b,1:0);}
template<class T> bool umax(T &a,const T &b){return (a<b?a=b,1:0);}
const ll inf=1e18;
signed main(){
fast_resp;
int n;
cin>>n;
vec<vec<int>>a(n,vec<int>(3));
vec<int>mx(3);
for(int i=0;i<n;i++){
for(int j=0;j<3;j++)
cin>>a[i][j],umax(mx[j],a[i][j]);
}
vec<int>ans;
int mxt=-1;
// for(i)
for(int i=0;i<n;i++){
for(int j=0;j<n;j++){
for(int k=0;k<n;k++){
if(a[i][0]>max(a[j][0],a[k][0]) &&
a[j][1]>max(a[i][1],a[k][1]) &&
a[k][2]>max(a[i][2],a[j][2])){
if(mx[0]==a[i][0] || mx[1]==a[i][1] || mx[2]==a[i][2]){
umax(mxt,a[i][0]+a[j][1]+a[k][2]);
// ans={i,j,k};
}
}
}
}
}
cout<<mxt;
// if(mxt==-1){
// cout<<-1;
// return 0;
// }
return 0;
}
/*
*/
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