이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<bits/stdc++.h>
using namespace std;
#pragma GCC target ("avx2")
#pragma GCC optimization ("O3")
#pragma GCC optimization ("unroll-loops")
int n, m, q;
pair< int, pair<int,int> > edg[100005];
vector<int> f[100005], b[100005], t[100005];
int x[100005], y[100005];
int dsu[100005];
int find(int x) {
if(dsu[x]==x) return x;
return dsu[x] = find(dsu[x]);
}
void merge(int x) {
dsu[find(edg[x].second.first)] = find(edg[x].second.second);
}
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
cin >> n >> m;
for(int i=1; i<=m; i++) {
cin >> edg[i].second.first >> edg[i].second.second >> edg[i].first;
}
sort(edg+1, edg+m+1);
for(int i=1; i<=m; i++) {
b[i].push_back(i);
for(int j=1; j<=n; j++) dsu[j] = j;
bool tmp = false;
x[i] = -1;
for(int j:b[i-1]) {
if(find(edg[j].second.first)!=find(edg[j].second.second)) {
merge(j);
if(find(edg[i].second.first)==find(edg[i].second.second) && !tmp) {
tmp = true;
x[i] = (edg[j].first + edg[i].first + 2) / 2;
}
else b[i].push_back(j);
}
}
}
for(int i=m; i>=1; i--) {
f[i].push_back(i);
for(int j=1; j<=n; j++) dsu[j] = j;
bool tmp = false;
y[i] = 2e9;
for(int j:f[i+1]) {
if(find(edg[j].second.first)!=find(edg[j].second.second)) {
merge(j);
if(find(edg[i].second.first)==find(edg[i].second.second) && !tmp) {
tmp = true;
y[i] = (edg[j].first + edg[i].first) / 2;
}
else f[i].push_back(j);
}
}
}
for(int i=0; i<=m; i++) {
for(int j:b[i]) t[i].push_back(j);
for(int j:f[i+1]) t[i].push_back(j);
}
cin >> q;
while(q--) {
int v;
cin >> v;
int pos = upper_bound(edg+1, edg+m+1, make_pair(v, make_pair((int)1e9, (int)1e9))) - edg - 1;
long long ans = 0;
for(int i:t[pos]) {
if(v>=x[i] && v<=y[i]) {
ans += abs(v-edg[i].first);
}
}
cout << ans << "\n";
}
}
컴파일 시 표준 에러 (stderr) 메시지
reconstruction.cpp:5: warning: ignoring '#pragma GCC optimization' [-Wunknown-pragmas]
5 | #pragma GCC optimization ("O3")
|
reconstruction.cpp:6: warning: ignoring '#pragma GCC optimization' [-Wunknown-pragmas]
6 | #pragma GCC optimization ("unroll-loops")
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