Submission #543428

#TimeUsernameProblemLanguageResultExecution timeMemory
543428SavicSBank (IZhO14_bank)C++17
52 / 100
1093 ms4880 KiB
#include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> #include <bits/stdc++.h> using namespace std; using namespace __gnu_pbds; typedef long long ll; typedef long double ld; typedef pair<int,int> pii; typedef pair<ll,ll> pll; typedef pair<ld,ld> pdd; #define ff(i,a,b) for(int i = a; i <= b; i++) #define fb(i,b,a) for(int i = b; i >= a; i--) #define trav(a,x) for (auto& a : x) #define sz(a) (int)(a).size() #define pb push_back #define fi first #define se second #define lb lower_bound #define ub upper_bound #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); template<typename T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; // os.order_of_key(k) the number of elements in the os less than k // *os.find_by_order(k) print the k-th smallest number in os(0-based) const int mod = 1000000007; const int inf = 1e9 + 5; const int mxN = 25; int n, m; int A[mxN]; int B[mxN]; bool dp[mxN][(1 << 20)]; int suma[(1 << 20)]; int main() { cin.tie(0)->sync_with_stdio(0); cin >> n >> m; ff(i,1,n)cin >> A[i]; ff(i,0,m - 1)cin >> B[i]; ff(mask,0,(1 << m) - 1){ int S = 0; ff(i,0,m - 1)if(mask & (1 << i))S += B[i]; suma[mask] = S; } dp[0][0] = 1; ff(i,1,n){ ff(mask,0,(1 << m) - 1){ for(int sub = mask; ;sub = (sub - 1) & mask){ dp[i][mask] |= dp[i - 1][sub] & (suma[mask ^ sub] == A[i]); if(dp[i][mask] == 1)break; if(sub == 0)break; } } } ff(mask,0,(1 << m) - 1){ if(dp[n][mask] == 1){ cout << "YES" << '\n'; return 0; } } cout << "NO" << '\n'; return 0; } /* 1 5 8 4 2 5 1 3 2 6 9 10 5 4 8 6 3 11 // probati bojenje sahovski */
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