이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
ll tree[1 << 21];
ll v[1 << 21];
const ll inf = 0x3f3f3f3f3f3f3f3f;
void update(int le, int ri, ll val, int nodele, int noderi, int node) {
if (le > noderi || ri < nodele)return;
if (le <= nodele && noderi <= ri) {
v[node] += val;
tree[node] += val;
return;
}
int mid = (nodele + noderi) / 2;
update(le, ri, val, nodele, mid, node * 2);
update(le, ri, val, mid + 1, noderi, node * 2 + 1);
tree[node] = min(tree[node * 2], tree[node * 2 + 1])+v[node];
}
int n, m, b, p;
vector<tuple<int, int, int> > vec[1000005];
bool possi(int k) {
memset(tree, 0, sizeof(tree));
memset(v, 0, sizeof(v));
for (int i = 1; i <= n; i++) {
for (auto v : vec[i]) {
int y1, y2, c;
tie(y1, y2, c) = v;
if (c > 0) update(max(1, y1 - k + 1), min(m - k + 1, y2), c, 1, m - k + 1, 1);
}
if (i >= k) {
for (auto v : vec[i - k]) {
int y1, y2, c;
tie(y1, y2, c) = v;
if (c < 0) update(max(1, y1 - k + 1), min(m - k + 1, y2), c, 1, m - k + 1, 1);
}
}
if (i >= k && tree[1] <= b) return true;
}
return false;
}
int main() {
scanf("%d%d%d%d", &n, &m, &b, &p);
for (int i = 0; i < p; i++) {
int x1, y1, x2, y2, c;
scanf("%d%d%d%d%d", &x1, &y1, &x2, &y2, &c);
vec[x1].emplace_back(y1, y2, c);
vec[x2].emplace_back(y1, y2, -c);
}
int le, ri, ans, mid;
le = 1;
ri = m;
ans = 0;
while (le <= ri) {
mid = (le + ri) / 2;
if (possi(mid)) {
ans = mid;
le = mid + 1;
}
else ri = mid - 1;
}
printf("%d\n", ans);
return 0;
}
컴파일 시 표준 에러 (stderr) 메시지
pyramid_base.cpp: In function 'int main()':
pyramid_base.cpp:42:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
scanf("%d%d%d%d", &n, &m, &b, &p);
~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~
pyramid_base.cpp:45:8: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
scanf("%d%d%d%d%d", &x1, &y1, &x2, &y2, &c);
~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
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