제출 #542176

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
542176		Alex_tz307	Colouring a rectangle (eJOI19_colouring)	C++17	20 / 100	533 ms	23532 KiB

colouring

#include <bits/stdc++.h>

using namespace std;

const int kN = 2e5;
const int64_t INF = 2e18L;
int a[2 * kN], v[1 + kN];
tuple<int, int, int> intervals[2 * kN];
vector<pair<int, int>> rEnd[1 + kN];

void minSelf(int64_t &x, int64_t y) {
  if (y < x) {
    x = y;
  }
}

struct ST {
  int n;
  vector<int64_t> t, lazy;

  ST(int N) : n(N) {
    int dim = 1;
    while (dim < n + 1) {
      dim *= 2;
    }
    dim *= 2;
    t.resize(dim);
    lazy.resize(dim);
  }

  void push(int x) {
    if (lazy[x] == 0) {
      return;
    }
    for (int y = 2 * x; y <= 2 * x + 1; ++y) {
      t[y] += lazy[x];
      lazy[y] += lazy[x];
    }
    lazy[x] = 0;
  }

  void rangeAdd(int x, int lx, int rx, int st, int dr, int64_t v) {
    if (st <= lx && rx <= dr) {
      t[x] += v;
      lazy[x] += v;
      return;
    }
    push(x);
    int mid = (lx + rx) / 2;
    if (st <= mid) {
      rangeAdd(x * 2, lx, mid, st, dr, v);
    }
    if (mid < dr) {
      rangeAdd(x * 2 + 1, mid + 1, rx, st, dr, v);
    }
    t[x] = min(t[x * 2], t[x * 2 + 1]);
  }

  void rangeAdd(int st, int dr, int64_t v) {
    rangeAdd(1, 0, n, st, dr, v);
  }

  int64_t query(int x, int lx, int rx, int st, int dr) {
    if (st <= lx && rx <= dr) {
      return t[x];
    }
    push(x);
    int mid = (lx + rx) / 2;
    int64_t ans = INF;
    if (st <= mid) {
      minSelf(ans, query(x * 2, lx, mid, st, dr));
    }
    if (mid < dr) {
      minSelf(ans, query(x * 2 + 1, mid + 1, rx, st, dr));
    }
    return ans;
  }

  int64_t query(int st, int dr) {
    return query(1, 0, n, st, dr);
  }
};

int64_t solve(int n) {
  ST t(n);
  for (int i = 1; i <= n; ++i) {
    t.rangeAdd(i, i, t.query(0, i - 1));
    t.rangeAdd(0, i - 1, v[i]);
    for (auto it : rEnd[i]) {
      int start, cost;
      tie(start, cost) = it;
      t.rangeAdd(start, i, cost);
    }
  }
  return t.t[1];
}

void testCase() {
  int n, m;
  cin >> n >> m;
  int N = n + m - 1;
  for (int i = 1; i <= N; ++i) {
    cin >> a[i];
  }
  int cost;
  for (int i = 1; i <= N; ++i) {
    cin >> cost;
    int y = min(i - 1, m - 1);
    int x = i - 1 - y;
    int index = x - y + m;
    int len = min(i, N - i + 1);
    intervals[i] = {index, len, cost};
  }
  int64_t ans = 0;
  for (int par = 0; par <= 1; ++par) {
    if (par == 0 && n == 1 && m == 1) {
      continue;
    }
    int p = get<0>(intervals[2 - par]) % 2;
    int M = (N + p) / 2;
    for (int i = 2 - p; i <= N; i += 2) {
      v[(i + p) / 2] = a[i];
    }
    for (int i = 1; i <= M; ++i) {
      rEnd[i].clear();
    }
    for (int i = 2 - par; i <= N; i += 2) {
      int index, len, cost;
      tie(index, len, cost) = intervals[i];
      rEnd[(index + 1) / 2 + len - 1].emplace_back((index + 1) / 2, cost);
    }
    ans += solve(M);
  }
  cout << ans << '\n';
}

int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(nullptr);
  int tests = 1;
  for (int tc = 0; tc < tests; ++tc) {
    testCase();
  }
  return 0;
}

• Subtask 1: 0 / 10
• Subtask 2: 0 / 10
• Subtask 3: 0 / 10
• Subtask 4: 0 / 20
• Subtask 5: 0 / 10
• Subtask 6: 20 / 20
• Subtask 7: 0 / 20