이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
struct Line {
long long m, b;
Line(long long _m, long long _b) : m(_m), b(_b) {}
long long operator()(long long x) { return m * x + b; }
friend long double intersect(const Line &l1, const Line &l2) {
return (long double)(l2.b - l1.b) / (long double)(l1.m - l2.m);
}
friend ostream& operator<<(ostream &os, const Line &l) {
return os << '{' << l.m << "x + " << l.b << '}';
}
};
int main() {
int N, K;
cin >> N >> K;
vector<long long> A(N + 1), P(N + 1, 0);
for (int i = 1; i <= N; i++) {
cin >> A[i];
P[i] = P[i - 1] + A[i];
}
array<vector<long long>, 2> dp;
dp[0].assign(N + 1, 0), dp[1].assign(N + 1, 0);
vector<vector<int>> par(K + 2, vector<int>(N + 1, 0));
for (int k = 1; k <= K + 1; k++) {
deque<pair<Line, int>> dq;
for (int i = 1; i <= N; i++) {
Line l(P[i - 1], dp[0][i - 1] - P[i - 1] * P[N]);
while (dq.size() >= 2 && intersect(l, dq[dq.size() - 2].first) >= intersect(l, dq[dq.size() - 1].first))
dq.pop_back();
dq.emplace_back(move(l), i - 1);
while (dq.size() >= 2 && dq[0].first(P[i]) <= dq[1].first(P[i]))
dq.pop_front();
dp[1][i] = dq[0].first(P[i]) + P[i] * P[N] - P[i] * P[i];
par[k][i] = dq[0].second;
}
copy(dp[1].begin(), dp[1].end(), dp[0].begin());
}
cout << dp[0][N] << '\n';
vector<int> ans;
for (int k = K + 1, c = N; k > 0; k--) {
if (c != N)
ans.push_back(c);
c = par[k][c];
}
reverse(ans.begin(), ans.end());
for (int c : ans)
cout << c << ' ';
cout << '\n';
}
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