Submission #540433

#	Time	Username	Problem	Language	Result	Execution time	Memory
540433		omohamadooo	구경하기 (JOI13_watching)	C++17	50 / 100	230 ms	31736 KiB

watching

#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>
#define ll long long
#define pb push_back
#define endl '\n'
#define pii pair<ll,ll>
#define F first
#define S second
#define double long double
#define all(x) (x).begin(),(x).end()

using namespace std;
using namespace __gnu_pbds;

typedef tree<ll , null_type , less_equal<ll> ,rb_tree_tag ,tree_order_statistics_node_update >ordered_set;

const int MOD = 1e9 + 7;
const int  N=1e6 + 7 ;
const ll INF= 1e18+10;

struct trp{ll F,S,T;};

ll po1(ll x,ll y)
{
    ll ans = 1;
    while(y){
        if( y & 1 ) ans *=x;
        y /= 2;
        x *=x;
        x %= MOD;
        ans %= MOD;
    }
    return ans;
}

ll n , p , q;
ll a[N];
ll dp[2005][2005];

bool ok(ll w)
{
    for(ll i= 0; i <= p ; i ++) dp[0][i] = 0;
    for(ll i= 1 ; i <= n ; i ++){
        ll ans1 = -1;
        ll ans2 = -1;
        for(ll j = 1 ; j <= i ; j ++){
            if(ans1 == -1 && a[i] - a[j] + 1<= w){
                ans1 = j;
            }
            if(ans2 == -1 && a[i] - a[j] + 1 <= 2 * w) ans2 = j;
        }

        dp[i][0] = dp[ans2 - 1][0] + 1;
        if(w == 1 && i == 2) cout << ans2 << endl;
        for(ll j = 1 ; j <= p ; j ++){
            dp[i][j] = min(dp[ans1-1][j-1] , dp[ans2 - 1][j] + 1);
        }
    }
    return dp[n][p] <= q;
}

void solve()
{
    cin >> n >> p >> q;
    for(ll i=1 ;i <= n ; i++) cin >> a[i];
    sort(a + 1 , a + n + 1);
    if(p+q >= n){
        cout << 1 <<endl;
        return;
    }
    ll l = 1 , r = MOD , mid;
    while(l < r){
        mid = (l + r)/2;
        if(ok(mid)) r = mid;
        else l = mid + 1;
    }
    cout << l << endl;
}

int main(){
    //ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
	//freopen(".in" , "r" , stdin);freopen(".out" , "w" , stdout);
	int t = 1;
    //cin >> t;
	while(t--) {solve() ; }
}

• Subtask 1: 50 / 50
• Subtask 2: 0 / 50