이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
#ifdef LOCAL
#include "debug.hpp"
#else
#define debug(...) "MJ >> LAMELO"
#endif
const int B = 800;
struct DSU {
vector<int> f, siz, st;
DSU(int n) : f(n), siz(n, 1) {
iota(f.begin(), f.end(), 0);
}
int find(int x) {
while (x != f[x]) {
// x = f[x] = f[f[x]];
x = f[x];
}
return x;
}
bool same(int x, int y) {
return find(x) == find(y);
}
bool merge(int x, int y) {
x = find(x);
y = find(y);
if (x == y) {
return false;
}
if (siz[y] > siz[x]) {
swap(x, y);
}
siz[x] += siz[y];
f[y] = x;
st.push_back(y);
return true;
}
int size(int x) {
return siz[find(x)];
}
void rollback() {
if (!st.empty()) {
int x = st.back();
st.pop_back();
siz[f[x]] -= siz[x];
f[x] = x;
}
}
};
int main() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
int n, m;
cin >> n >> m;
vector<array<int, 3>> e;
for (int i = 0; i < m; i++) {
int u, v, d;
cin >> u >> v >> d;
--u;
--v;
e.push_back({u, v, d});
}
int q;
cin >> q;
vector<array<int, 3>> Q(q);
for (int i = 0; i < q; i++) {
cin >> Q[i][0] >> Q[i][1] >> Q[i][2];
Q[i][1]--;
}
vector<int> ans(q);
for (int L = 0; L < q; L += B) {
vector<int> mark(m);
vector<int> same;
vector<int> diff;
vector<int> t2;
int R = min(L + B, q);
for (int i = L; i < R; i++) {
if (Q[i][0] == 1) {
mark[Q[i][1]] = 1;
diff.push_back(Q[i][1]);
} else {
t2.push_back(i);
}
}
vector<vector<int>> c(B);
for (int i = L; i < R; i++) {
if (Q[i][0] == 1) {
e[Q[i][1]][2] = Q[i][2];
} else {
for (int j : diff) {
if (e[j][2] >= Q[i][2]) {
c[i - L].push_back(j);
}
}
}
}
for (int i = 0; i < m; i++) {
if (!mark[i]) {
same.push_back(i);
}
}
sort(t2.begin(), t2.end(), [&](int i, int j) {
return Q[i][2] > Q[j][2];
});
sort(same.begin(), same.end(), [&](int i, int j) {
return e[i][2] > e[j][2];
});
DSU d(n);
int ptr = 0;
for (int i : t2) {
while (ptr < (int) same.size() && e[same[ptr]][2] >= Q[i][2]) {
d.merge(e[same[ptr]][0], e[same[ptr]][1]);
ptr++;
}
int cnt = 0;
for (int j : c[i - L]) {
if (d.merge(e[j][0], e[j][1])) {
cnt++;
}
}
ans[i] = d.size(Q[i][1]);
while (cnt--) {
d.rollback();
}
}
}
for (int i = 0; i < q; i++) {
if (Q[i][0] == 2) {
cout << ans[i] << '\n';
}
}
}
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