Submission #538196

#TimeUsernameProblemLanguageResultExecution timeMemory
538196fhvirusTreatment Project (JOI20_treatment)C++17
100 / 100
223 ms33932 KiB
// Knapsack DP is harder than FFT. #include<bits/stdc++.h> using namespace std; typedef long long ll; typedef pair<int,int> pii; #define ff first #define ss second #define pb emplace_back #define AI(x) begin(x),end(x) #ifdef OWO #define debug(args...) SDF(#args, args) #define OIU(args...) ostream& operator<<(ostream&O,args) #define LKJ(S,B,E,F) template<class...T>OIU(S<T...>s){O<<B;int c=0;for(auto i:s)O<<(c++?", ":"")<<F;return O<<E;} LKJ(vector,'[',']',i)LKJ(deque,'[',']',i)LKJ(set,'{','}',i)LKJ(multiset,'{','}',i)LKJ(unordered_set,'{','}',i)LKJ(map,'{','}',i.ff<<':'<<i.ss)LKJ(unordered_map,'{','}',i.ff<<':'<<i.ss) template<class...T>void SDF(const char* s,T...a){int c=sizeof...(T);if(!c){cerr<<"\033[1;32mvoid\033[0m\n";return;}(cerr<<"\033[1;32m("<<s<<") = (",...,(cerr<<a<<(--c?", ":")\033[0m\n")));} template<class T,size_t N>OIU(array<T,N>a){return O<<vector<T>(AI(a));}template<class...T>OIU(pair<T...>p){return O<<'('<<p.ff<<','<<p.ss<<')';}template<class...T>OIU(tuple<T...>t){return O<<'(',apply([&O](T...s){int c=0;(...,(O<<(c++?", ":"")<<s));},t),O<<')';} #else #define debug(...) ((void)0) #endif struct Lisan: vector<int> { void done() { sort(begin(), end()); erase(unique(begin(), end()), end()); } int operator () (const int& v) const { return std::lower_bound(begin(), end(), v) - begin(); } int upper_bound (const int& v) const { return std::upper_bound(begin(), end(), v) - begin(); } }; struct Treatment { int T, L, R, C, x, y; Treatment (const int& _T, const int& _L, const int& _R, const int& _C): T(_T), L(_L), R(_R), C(_C), x(L + T), y(L - T) {} }; struct SegmentTree { int n; vector<vector<pair<int, int>>> val; SegmentTree (const int& _n): n(_n), val(4 << __lg(n)) {} void insert(int i, int l, int r, int p, pair<int, int> v) { if (l + 1 == r) { val[i].push_back(v); return; } int m = (l + r) / 2; if (p < m) insert(i * 2, l, m, p, v); else insert(i * 2 + 1, m, r, p, v); } void insert(int x, int y, int i) { insert(1, 0, n, x, pair<int, int>(y, i)); } void build(int i, int l, int r) { if (l + 1 == r) { sort(begin(val[i]), end(val[i]), greater<pair<int, int>>()); return; } int m = (l + r) / 2; build(i * 2, l, m); build(i*2+1, m, r); val[i].reserve(val[i * 2].size() + val[i*2+1].size()); merge(begin(val[i * 2]), end(val[i * 2]), begin(val[i*2+1]), end(val[i*2+1]), back_inserter(val[i]), greater<pair<int, int>>()); } void build() { build(1, 0, n); } void collect(int i, int l, int r, int x, int y, vector<int>& ids) { debug(i, l, r, x, y, val[i]); if (x <= l) return; if (r <= x) { while (!val[i].empty()) { auto [yi, id] = val[i].back(); if (yi <= y) { ids.emplace_back(id); val[i].pop_back(); } else break; } return; } int m = (l + r) / 2; collect(i * 2, l, m, x, y, ids); if (m < x) collect(i * 2 + 1, m, r, x, y, ids); } void collect(int x, int y, vector<int>& ids) { collect(1, 0, n, x, y, ids); } }; int main() { ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); int N, M; cin >> N >> M; vector<Treatment> ts; Lisan lisan; ts.reserve(M); lisan.reserve(M); for (int T, L, R, C, i = 0; i < M; ++i) { cin >> T >> L >> R >> C; ts.emplace_back(T, L, R, C); lisan.emplace_back(ts.back().x); } lisan.done(); debug(lisan.size(), lisan); SegmentTree sgt(lisan.size()); for (int i = 0; i < M; ++i) { const auto& [T, L, R, C, x, y] = ts[i]; sgt.insert(lisan(x), y, i); debug(T, L, R, lisan(x), y, i); } sgt.build(); vector<long long> dis(M, LLONG_MAX); priority_queue<pair<long long, int>, vector<pair<long long, int>>, greater<pair<long long, int>>> pq; for (int i = 0; i < M; ++i) { if (ts[i].L == 1) { dis[i] = ts[i].C; pq.emplace(dis[i], i); } } vector<int> vs; vs.reserve(M); while (!pq.empty()) { auto [d, u] = pq.top(); pq.pop(); assert(d == dis[u]); int x = ts[u].R + ts[u].T + 1; int y = ts[u].R - ts[u].T + 1; debug(u, x, y); sgt.collect(lisan.upper_bound(x), y, vs); debug(vs); for (const int& v: vs) { if (d + ts[v].C < dis[v]) { dis[v] = d + ts[v].C; pq.emplace(dis[v], v); } } vs.clear(); } long long ans = LLONG_MAX; for (int i = 0; i < M; ++i) { if (ts[i].R == N) { ans = min(ans, dis[i]); } } if (ans == LLONG_MAX) ans = -1; cout << ans << '\n'; return 0; }
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