답안 #537402

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
537402 2022-03-15T04:58:14 Z Stro256 Prosjecni (COCI16_prosjecni) C++14
120 / 120
2 ms 852 KB
#include<bits/stdc++.h>
using namespace std;

#define FOR(i,a,b) for(int i = (a) ; i<(b) ; i++)
#define F0R(i,a) FOR(i,0,a)
#define ROF(i,a,b) for(int i = (b)-1 ; i>=(a) ; i--)
#define R0F(i,a) ROF(i,0,a)
#define rep(i,a,b) FOR(i,a,b)
#define REP(a) F0R(_,a)
#define each(e,a) for(auto &e : (a))
#define sz(v) (int)(v).size()
#define all(v) (v).begin(),(v).end()
#define rall(v) (v).rbegin(),(v).rend()
#define rsz resize
#define pb push_back
#define f first
#define s second
#define pf push_front
#define ft front()
#define bk back()
#define eb emplace_back
#define lb lower_bound
#define ub upper_bound
#define tcT template<class T
#define tcTU tcT, class U
#define nl "\n"

using ll = long long;
using vi = vector<int>;
using vl = vector<ll>;
using vb = vector<bool>;
using pi = pair<int,int>;
using vpi = vector<pi>;
using str = string;
using vs = vector<str>;
using db = long double;
using pl = pair<ll,ll>;
using pd = pair<db,db>;
tcT> using V = vector<T>;
tcT> using pqg = priority_queue<T,vector<T>,greater<T>>;
tcTU> using PR = pair<T,U>;
tcT, int SZ> using AR = array<T, SZ>;

const int MOD = 1e9+7;
const ll INF = 1e18;
const int dx[] = {-1,0,1,0}, dy[] = {0,-1,0,1};

constexpr int bits(int x) { return x == 0 ? 0 : 31 - __builtin_clz(x); }
constexpr bool onbit(int msk, int i) { return msk>>i&1; }
constexpr ll p2(int x) { return 1LL<<x; }
constexpr int pct(int x) { return __builtin_popcount(x); }
constexpr int lg2(int x) { return x == 0 ? 0 : 31 - __builtin_clz(x); }; //int only

tcT> bool ckmin(T&a, const T&b) { return b < a ? a = b,1 : 0; }
tcT> bool ckmax(T&a, const T&b) { return b > a ? a = b,1 : 0; }

ll cdiv(ll a, ll b) { return a/b+((a^b)>0&&a%b); }
ll fdiv(ll a, ll b) { return a/b-((a^b)<0&&a%b); }

tcTU> T fstTrue(T lo, T hi, U f) {
    hi++; assert(lo <= hi);
    while (lo < hi) {
        T mid = lo+(hi-lo)/2;
        f(mid) ? hi = mid : lo = mid+1;
    }
    return lo;
}
tcTU> T lstTrue(T lo, T hi, U f) {
    lo--; assert(lo <= hi);
    while (lo < hi) {
        T mid = lo+(hi-lo+1)/2;
        f(mid) ? lo = mid : hi = mid-1;
    }
    return lo;
}

tcT> void remDup(V<T> &v) {
    sort(all(v)); v.erase(unique(all(v)), end(v)); }
void DBG() { cerr << "]\n"; }
template<class H, class... T> void DBG(H h, T... t) {
    cerr << h; if(sizeof...(t)) cerr << ", ";
    DBG(t...);
}
#ifdef LOCAL
#define dbg(...) cerr << "LINE(" << __LINE__ << ") -> [" << #__VA_ARGS__ << "]: [", DBG(__VA_ARGS__)
#else
#define dbg(...) 0
#endif // LOCAL

void setPrec() { cout << fixed << setprecision(16); }
void setIO(string NAME = "") {
    cin.tie(0)->sync_with_stdio(0);
    setPrec();
    if(sz(NAME)) {
        freopen((NAME + ".inp").c_str(),"r",stdin);
        freopen((NAME + ".out").c_str(),"w",stdout);
    }
}

const int MX = 1e3+5;
int N;
ll ans[MX][MX];

void solve() {
    cin>>N;
    if(N == 1) {
        cout << "1\n";
        return;
    }
    if(N == 2) {
        cout << "-1\n";
        return;
    }
    F0R(i,N-1) ans[0][i] = i+1;
    ans[0][N-1] = N*(N-1)/2;
    FOR(i,1,N) {
        F0R(j,N) ans[i][j] = ans[i-1][j] + ans[0][N-1];
    }
    F0R(j,N) {
        ans[N-1][j] = N*ans[N-2][j];
        F0R(i,N-1) ans[N-1][j] -= ans[i][j];
    }
    F0R(i,N) {
        F0R(j,N) cout << ans[i][j] << " ";
        cout << nl;
    }
}

int main() {
    setIO();

    int t=1;
    //cin>>t;
    while(t-->0) {
        solve();
    }

    return 0;
}

Compilation message

prosjecni.cpp: In function 'void setIO(std::string)':
prosjecni.cpp:95:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   95 |         freopen((NAME + ".inp").c_str(),"r",stdin);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prosjecni.cpp:96:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   96 |         freopen((NAME + ".out").c_str(),"w",stdout);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 340 KB Output is correct
2 Correct 1 ms 340 KB Output is correct
3 Correct 1 ms 340 KB Output is correct
4 Correct 1 ms 340 KB Output is correct
5 Correct 1 ms 340 KB Output is correct
6 Correct 1 ms 456 KB Output is correct
7 Correct 1 ms 580 KB Output is correct
8 Correct 2 ms 840 KB Output is correct
9 Correct 1 ms 852 KB Output is correct
10 Correct 2 ms 852 KB Output is correct