oj.uz

답안 #537138

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
537138 2022-03-14T15:38:33 Z BossBobster 경주 (Race) (IOI11_race) C++17
0 / 100
 2 ms 4948 KB 
#include <iostream>
#include <string.h>
#include <random>
#include <fstream>
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <iomanip>
#include <algorithm>
#include <math.h>
#include <cmath>
#include <vector>
#include <stack>
#include <queue>
#include <bitset>
#include <map>
#include <set>
#include <unordered_map>
#include <unordered_set>
#include <complex>
#include <valarray>
using namespace std;
//#include <ext/pb_ds/assoc_container.hpp>
//#include <ext/pb_ds/tree_policy.hpp>
//using namespace __gnu_pbds;
//template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
typedef pair<int, int> pii;
typedef pair<int, string> pis;
typedef pair<int, short> pish;
typedef pair<string, string> pss;
typedef pair<int, char> pic;
typedef pair<pii, int> piii;
typedef pair<double, double> pdd;
typedef pair<float, float> pff;
typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
typedef unsigned int uint;
typedef pair<ll, ll> pll;
typedef pair<pll, ll> plll;
typedef pair<pll, ld> plld;
typedef pair<int, ll> pil;
typedef pair<ull, ull> pull;
typedef pair<ld, ld> pld;
typedef complex<double> cd;
//#define max(n, m) ((n>m)?n:m)
//#define min(n, m) ((n<m)?n:m)
#define f first
#define s second
#define input() ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define eps 1e-9
//#define cin fin

vector<pii> adj[200010];
int n, k, a, b, root;
int sz[200010];
int p[200010];
bitset<200010> vis;
int dfs1(int cur, int par)
{
    sz[cur] = 1;
    for(auto nx : adj[cur])
        if(nx.f != par && !vis[nx.f])
            sz[cur] += dfs1(nx.f, cur);
    return sz[cur];
}
int dfs2(int cur, int par, int n)
{
    for(auto nx : adj[cur])
        if(nx.f != par && sz[nx.f] > n/2 && !vis[nx.f])
            return dfs2(nx.f, cur, n);
    return cur;
}
int mx;
int ans = 2000000000;
unordered_map<int, int> cnt;
void dfs3(int cur, int par, int d, int num)
{
    if(d > k) return;
    mx = max(mx, d);
    if(cnt[k-d] != 0 || k-d == 0)
        ans = min(ans, num+cnt[k-d]);
    for(auto nx : adj[cur])
        if(nx.f != par && !vis[nx.f])
            dfs3(nx.f, cur, d+nx.s, num+1);
}
void dfs4(int cur, int par, int d, int num)
{
    if(d > k) return;
    mx = max(mx, d);
    if(cnt[d] == 0) cnt[d] = 2000000000;
    cnt[d] = min(cnt[d], num);
    for(auto nx : adj[cur])
        if(nx.f != par && !vis[nx.f])
            dfs4(nx.f, cur, d+nx.s, num+1);
}
void make(int cur, int par)
{
    int cent = dfs2(cur, par, dfs1(cur, par));
    vis[cent] = 1;
    mx = 0;
    for(auto it : adj[cent])
        if(!vis[it.f])
            dfs3(it.f, cent, it.s, 1), dfs4(it.f, cent, it.s, 1);
    cnt.clear();
    for(auto it : adj[cent])
        if(!vis[it.f])
            make(it.f, cent);
}
int best_path(int n2, int k2, int edges[][2], int nums[])
{
    for(int i = 0; i < n-1; i ++)
        adj[edges[i][0]].push_back({edges[i][1], nums[i]}), adj[edges[i][1]].push_back({edges[i][0], nums[i]});
    k = k2; n = n2;
    make(0, -1);
    return ((ans==2000000000)?-1:ans);
}

Subtask #1
0 / 9.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 2 ms 4948 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #2
0 / 12.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 2 ms 4948 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #3
0 / 22.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 2 ms 4948 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #4
0 / 57.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 2 ms 4948 KB Output isn't correct
2 Halted 0 ms 0 KB -