oj.uz

답안 #536940

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
536940 2022-03-14T07:55:38 Z wiwiho Unique Cities (JOI19_ho_t5) C++14
0 / 100
 268 ms 17840 KB 
#include <bits/stdc++.h>
#include <bits/extc++.h>

#define StarBurstStream ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);
#define iter(a) a.begin(), a.end()
#define riter(a) a.rbegin(), a.rend()
#define lsort(a) sort(iter(a))
#define gsort(a) sort(riter(a))
#define pb(a) push_back(a)
#define eb(a) emplace_back(a)
#define pf(a) push_front(a)
#define ef(a) emplace_front(a)
#define pob pop_back()
#define pof pop_front()
#define mp(a, b) make_pair(a, b)
#define F first
#define S second
#define mt make_tuple
#define gt(t, i) get<i>(t)
#define tomax(a, b) ((a) = max((a), (b)))
#define tomin(a, b) ((a) = min((a), (b)))
#define topos(a) ((a) = (((a) % MOD + MOD) % MOD))
#define uni(a) a.resize(unique(iter(a)) - a.begin())
#define printv(a, b) {bool pvaspace=false; \
for(auto pva : a){ \
    if(pvaspace) b << " "; pvaspace=true;\
    b << pva;\
}\
b << "\n";}

using namespace std;
using namespace __gnu_pbds;

typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;

using pii = pair<int, int>;
using pll = pair<ll, ll>;
using pdd = pair<ld, ld>;
using tiii = tuple<int, int, int>;

const ll MOD = 1000000007;
const ll MAX = 2147483647;

template<typename A, typename B>
ostream& operator<<(ostream& o, pair<A, B> p){
    return o << '(' << p.F << ',' << p.S << ')';
}

ll ifloor(ll a, ll b){
    if(b < 0) a *= -1, b *= -1;
    if(a < 0) return (a - b + 1) / b;
    else return a / b;
}

ll iceil(ll a, ll b){
    if(b < 0) a *= -1, b *= -1;
    if(a > 0) return (a + b - 1) / b;
    else return a / b;
}

int n, m;
vector<vector<int>> g;
vector<int> C;

void init(){
    g.resize(n + 1);
    C.resize(n + 1);
}

int fd = -1, fv = -1;
void dfsfar(int now, int p, int d){
    if(d > fd) fd = d, fv = now;
    for(int i : g[now]){
        if(i == p) continue;
        dfsfar(i, now, d + 1);
    }
}

struct Solver{

    vector<int> dep, cnt, dis, ans;
    vector<int> st;
    int tans = 0;

    void add(int id){
        st.eb(id);
        cnt[C[id]]++;
        if(cnt[C[id]] == 1) tans++;
    }
    void remove(){
        int id = st.back();
        st.pob;
        cnt[C[id]]--;
        if(cnt[C[id]] == 0) tans--;
    }

    void dfs1(int now, int p, int d){
        dis[now] = d;
        for(int i : g[now]){
            if(i == p) continue;
            dfs1(i, now, d + 1);
            dep[now] = max(dep[i] + 1, dep[now]);
        }
    }

    void dfs2(int now, int p){
        int mx1 = -1, mx2 = -1;
        for(int i : g[now]){
            if(i == p) continue;
            if(mx1 == -1 || dep[i] > dep[mx1]) swap(mx1, i);
            if(i == -1) continue;
            if(mx2 == -1 || dep[i] > dep[mx2]) swap(mx2, i);
        }
        if(mx1 == -1){
            ans[now] = tans;
            return;
        }

        if(mx2 != -1){
            while(!st.empty() && dis[st.back()] >= dis[now] - dep[mx2] - 1) remove();
        }
        add(now);
        dfs2(mx1, now);
        if(!st.empty() && st.back() == now) remove();

        while(!st.empty() && dis[st.back()] >= dis[now] - dep[mx1] - 1) remove();
        add(now);
        for(int i : g[now]){
            if(i == p || i == mx1) continue;
            dfs2(i, now);
        }
        if(!st.empty() && st.back() == now) remove();
        //cerr << "dfs2 " << now << " " << mx1 << " " << mx2 << "\n";
        //printv(st, cerr);
        ans[now] = tans;
    }

    void solve(int s){
        cnt.resize(n + 1);
        dep.resize(n + 1);
        dis.resize(n + 1);
        ans.resize(n + 1);

        dfs1(s, s, 0);
        dfs2(s, s);

        /*cerr << "solve " << s << "\n";
        printv(dep, cerr);
        printv(dis, cerr);
        printv(ans, cerr);*/
    }

};

int main(){
    StarBurstStream

    cin >> n >> m;
    init();
    for(int i = 0; i < n - 1; i++){
        int u, v;
        cin >> u >> v;
        g[u].eb(v);
        g[v].eb(u);
    }
    for(int i = 1; i <= n; i++) cin >> C[i];

    dfsfar(1, 1, 0);
    int v1 = fv;
    fv = -1; fd = -1;
    dfsfar(v1, v1, 0);
    int v2 = fv;
    //cerr << v1 << " " << v2 << "\n";

    Solver s1, s2;
    s1.solve(v1);
    s2.solve(v2);

    for(int i = 1; i <= n; i++){
        cout << max(s1.ans[i], s2.ans[i]) << "\n";
    }

    return 0;
}

Subtask #1
0 / 4.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 316 KB Output is correct
2 Incorrect 2 ms 460 KB Output isn't correct
3 Halted 0 ms 0 KB -

Subtask #2
0 / 32.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 145 ms 12612 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #3
0 / 32.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 268 ms 17840 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #4
0 / 32.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 316 KB Output is correct
2 Incorrect 2 ms 460 KB Output isn't correct
3 Halted 0 ms 0 KB -