제출 #536400

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
536400		Arnch	Financial Report (JOI21_financial)	C++17	100 / 100	663 ms	25752 KiB

Main

// oooo
/*
 har chi delet mikhad bebar ~
 gitar o ba khodet nabar! ~
 ;Amoo_Hasan;
*/

#include<bits/stdc++.h>
#pragma GCC optimize("O3,no-stack-protector,unroll-loops")
#pragma GCC target("avx2,fma")

using namespace std;

typedef long long ll;
typedef long double ld;

#define Sz(x) int((x).size())
#define All(x) (x).begin(), (x).end()
#define wtf(x) cout<<#x <<" : " <<x

constexpr ll inf = 1e18, N = 1e6 + 10, mod = 1e9 + 7, pr = 1000696969;

int n, d, a[N], l[N], r[N], dp[N];
set<int> bad, to;
vector<pair<int, int> > vc;

bool cmp(pair<int, int> p1, pair<int, int> p2) {
	if(p1.first != p2.first) return p1.first < p2.first;
	return p1.second > p2.second;
}

struct node {
	int val;
} x[N << 2];
void change(int l, int r, int ind, int val, int v) {
	if(r - l < 2) {
		x[v].val = val;
		return;
	}
	int mid = (l + r) >> 1;
	if(ind < mid) change(l, mid, ind, val, 2 * v);
	else change(mid, r, ind, val, 2 * v + 1);
	x[v].val = max(x[2 * v].val, x[2 * v + 1].val);
}	
int get(int l, int r, int s, int e, int v) {
	if(r <= s || l >= e) return 0;
	if(l >= s && r <= e) return x[v].val;
	int mid = (l + r) >> 1;
	return max(get(l, mid, s, e, 2 * v), get(mid, r, s, e, 2 * v + 1));
}

int main() {
    ios :: sync_with_stdio(0), cin.tie(0);
	
	cin >>n >>d;
	for(int i = 0; i < n; i++) cin >>a[i], vc.push_back({a[i], i});
	sort(All(vc), cmp);
	
	for(int i = 0; i < n; i++) l[i] = -1, r[i] = n;

	for(auto i : vc) {
		int ind = i.second;
		auto it = to.lower_bound(ind);
		if(it != to.end()) {
			l[*it] = ind, r[ind] = *it;
			if(*it - ind <= d) {
				bad.erase(*it);
			}
		}
		if(it != to.begin()) {
			it--;
			l[ind] = *it, r[*it] = ind;
		}
		to.insert(ind);
		if(ind - l[ind] > d) bad.insert(ind);
		dp[ind] = 1;
		if(ind != 0) {
			auto pos = bad.upper_bound(ind);
			if(pos == bad.begin()) {
				dp[ind] += get(0, n, 0, ind, 1);
			}
			else {
				pos--;
				int j = *pos;
				if(j != ind) 
					dp[ind] += get(0, n, j, ind, 1);
			}
		}
		change(0, n, ind, dp[ind], 1);
	}
	
	int ans = 0;
	for(int i = 0; i < n; i++) ans = max(ans, dp[i]);

	cout<<ans;

    return 0;
}

• Subtask 1: 14 / 14
• Subtask 2: 14 / 14
• Subtask 3: 20 / 20
• Subtask 4: 12 / 12
• Subtask 5: 5 / 5
• Subtask 6: 35 / 35