oj.uz

답안 #535935

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
535935 2022-03-11T22:08:52 Z inksamurai Volontiranje (COCI21_volontiranje) C++17
0 / 110
 1 ms 240 KB 
#include <bits/stdc++.h>
// cut here
#ifdef _MSC_VER
#include <intrin.h>
#endif
 
namespace atcoder {
 
namespace internal {
 
int ceil_pow2(int n) {
    int x = 0;
    while ((1U << x) < (unsigned int)(n)) x++;
    return x;
}
 
int bsf(unsigned int n) {
#ifdef _MSC_VER
    unsigned long index;
    _BitScanForward(&index, n);
    return index;
#else
    return __builtin_ctz(n);
#endif
}
 
}  // namespace internal
 
}  // namespace atcoder
 
 
namespace atcoder {
 
template <class S, S (*op)(S, S), S (*e)()> struct segtree {
  public:
    segtree() : segtree(0) {}
    segtree(int n) : segtree(std::vector<S>(n, e())) {}
    segtree(const std::vector<S>& v) : _n(int(v.size())) {
        log = internal::ceil_pow2(_n);
        size = 1 << log;
        d = std::vector<S>(2 * size, e());
        for (int i = 0; i < _n; i++) d[size + i] = v[i];
        for (int i = size - 1; i >= 1; i--) {
            update(i);
        }
    }
 
    void set(int p, S x) {
        assert(0 <= p && p < _n);
        p += size;
        d[p] = x;
        for (int i = 1; i <= log; i++) update(p >> i);
    }
 
    S get(int p) {
        assert(0 <= p && p < _n);
        return d[p + size];
    }
 
    S prod(int l, int r) {
        assert(0 <= l && l <= r && r <= _n);
        S sml = e(), smr = e();
        l += size;
        r += size;
 
        while (l < r) {
            if (l & 1) sml = op(sml, d[l++]);
            if (r & 1) smr = op(d[--r], smr);
            l >>= 1;
            r >>= 1;
        }
        return op(sml, smr);
    }
 
    S all_prod() { return d[1]; }
 
    template <bool (*f)(S)> int max_right(int l) {
        return max_right(l, [](S x) { return f(x); });
    }
    template <class F> int max_right(int l, F f) {
        assert(0 <= l && l <= _n);
        assert(f(e()));
        if (l == _n) return _n;
        l += size;
        S sm = e();
        do {
            while (l % 2 == 0) l >>= 1;
            if (!f(op(sm, d[l]))) {
                while (l < size) {
                    l = (2 * l);
                    if (f(op(sm, d[l]))) {
                        sm = op(sm, d[l]);
                        l++;
                    }
                }
                return l - size;
            }
            sm = op(sm, d[l]);
            l++;
        } while ((l & -l) != l);
        return _n;
    }
 
    template <bool (*f)(S)> int min_left(int r) {
        return min_left(r, [](S x) { return f(x); });
    }
    template <class F> int min_left(int r, F f) {
        assert(0 <= r && r <= _n);
        assert(f(e()));
        if (r == 0) return 0;
        r += size;
        S sm = e();
        do {
            r--;
            while (r > 1 && (r % 2)) r >>= 1;
            if (!f(op(d[r], sm))) {
                while (r < size) {
                    r = (2 * r + 1);
                    if (f(op(d[r], sm))) {
                        sm = op(d[r], sm);
                        r--;
                    }
                }
                return r + 1 - size;
            }
            sm = op(d[r], sm);
        } while ((r & -r) != r);
        return 0;
    }
 
  private:
    int _n, size, log;
    std::vector<S> d;
 
    void update(int k) { d[k] = op(d[2 * k], d[2 * k + 1]); }
};
 
}  // namespace atcoder
// cut here 

using namespace std;
#define rep(i,n) for(int i=0;i<n;i++)
#define rng(i,x,n) for(int i=x;i<n;i++)
#define per(i,n) for(int i=n-1;i>=0;i--)
#define fi first
#define se second
#define pb push_back
#define sz(a) (int)a.size()
#define vec(...) vector<__VA_ARGS__>
#define _3HspL4A ios::sync_with_stdio(0),cin.tie(0)
typedef long long ll;
using pii=pair<int,int>;
using vi=vec(int);
void print(){cout<<"\n";}
template<class T,class...E>
void print(const T&v,const E&...u){cout<<v<<' ',print(u...);}
// e

pii op(pii l,pii r){
	if(l.fi==r.fi) return l.se>r.se?l:r;
	return l.fi>r.fi?l:r;
}
pii e(){
	return {0,-1};
}

int op1(int l,int r){
	return max(l,r);
}
int e1(){
	return -1;
}

signed main(){
_3HspL4A;
	int n;
	cin>>n;
	vi a(n);
	rep(i,n) cin>>a[i];
	vi id(n);
	rep(i,n){
		a[i]-=1;
		id[a[i]]=i;
	}
	int len;
	{
		set<int> st;
		for(auto x:a){
			if(!sz(st)){
				st.insert(x);
			}else{
				auto it=st.lower_bound(x);
				if(it!=st.end()){
					st.erase(it);
				}
				st.insert(x);
			}
		}
		len=sz(st);
	}
	atcoder::segtree<pii,op,e> seg(n);
	vi nxt(n);
	rep(i,n){
		int x=a[i];
		pii val=seg.prod(0,x);
		nxt[i]=val.se;
		val.fi++;
		val.se=x;
		seg.set(x,val);
	}
	pii p=seg.prod(0,n);
	assert(p.fi==len);
	vi layer;
	int i=id[p.se];
	while(1){
		layer.pb(i);
		if(nxt[i]==-1) break;
		i=id[nxt[i]];		
	}
	reverse(layer.begin(),layer.end());
	atcoder::segtree<int,op1,e1> nseg(a);
	for(auto v:layer){
		nseg.set(v,-1);
	}
	vec(vi) pns;
	pns.pb(layer);
	vi qol=layer;
	while(1){
		layer={};
		per(j,len){
			if(qol[j]>=n-1) break;
			bool pok=1;
			while(1){
				int val=nseg.prod(qol[j]+1,(j==len-1?n:qol[j+1]));
				if(val==-1){
					pok=0;
					break;
				}
				nseg.set(id[val],-1);
				if(!sz(layer) or a[layer.back()]>val){
					layer.pb(id[val]);
					qol[j]=id[val];
					break;
				}
			}
			if(!pok) break;
		}
		if(sz(layer)!=len) break;
		reverse(layer.begin(),layer.end());
		pns.pb(layer);
	}
	print(sz(pns),len);
	for(auto ids:pns){
		for(auto v:ids) cout<<v+1<<" ";
		print();
	}
//	
	return 0;
}

Subtask #1
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 1 ms 212 KB Output is correct
3 Correct 0 ms 212 KB Output is correct
4 Correct 1 ms 212 KB Output is correct
5 Correct 0 ms 212 KB Output is correct
6 Correct 0 ms 212 KB Output is correct
7 Correct 0 ms 212 KB Output is correct
8 Correct 0 ms 212 KB Output is correct
9 Correct 0 ms 212 KB Output is correct
10 Correct 0 ms 212 KB Output is correct
11 Correct 0 ms 212 KB Output is correct
12 Incorrect 0 ms 240 KB Output isn't correct
13 Halted 0 ms 0 KB -

Subtask #2
0 / 40.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 1 ms 212 KB Output is correct
3 Correct 0 ms 212 KB Output is correct
4 Correct 1 ms 212 KB Output is correct
5 Correct 0 ms 212 KB Output is correct
6 Correct 0 ms 212 KB Output is correct
7 Correct 0 ms 212 KB Output is correct
8 Correct 0 ms 212 KB Output is correct
9 Correct 0 ms 212 KB Output is correct
10 Correct 0 ms 212 KB Output is correct
11 Correct 0 ms 212 KB Output is correct
12 Incorrect 0 ms 240 KB Output isn't correct
13 Halted 0 ms 0 KB -

Subtask #3
0 / 60.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 1 ms 212 KB Output is correct
3 Correct 0 ms 212 KB Output is correct
4 Correct 1 ms 212 KB Output is correct
5 Correct 0 ms 212 KB Output is correct
6 Correct 0 ms 212 KB Output is correct
7 Correct 0 ms 212 KB Output is correct
8 Correct 0 ms 212 KB Output is correct
9 Correct 0 ms 212 KB Output is correct
10 Correct 0 ms 212 KB Output is correct
11 Correct 0 ms 212 KB Output is correct
12 Incorrect 0 ms 240 KB Output isn't correct
13 Halted 0 ms 0 KB -