제출 #533875

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
533875		hollwo_pelw	밀림 점프 (APIO21_jumps)	C++17	27 / 100	1220 ms	33712 KiB

jumps

#include "jumps.h"

#include <bits/stdc++.h>
using namespace std;

const int N = 2e5 + 5;

int big_jmp[18][N], sml_jmp[18][N];
int h[N], ljmp[N], rjmp[N];

void init(int n, vector<int> a) {
	a.insert(a.begin(), n + 1); // to 1-based

	static int st[N];

	for (int i = 1, top = 0; i <= n; i++) {
		while (top && a[st[top]] < a[i])
			rjmp[st[top --]] = i;
		st[++ top] = i;
	}

	for (int i = n, top = 0; i >= 1; i--) {
		while (top && a[st[top]] < a[i])
			ljmp[st[top --]] = i;
		st[++ top] = i;
	}

	for (int i = 1; i <= n; i++) {
		big_jmp[0][i] = a[rjmp[i]] > a[ljmp[i]] ? rjmp[i] : ljmp[i];
		sml_jmp[0][i] = a[rjmp[i]] < a[ljmp[i]] ? rjmp[i] : ljmp[i];
	}

	for (int i = 1; i < 18; i++)
		for (int j = 1; j <= n; j++) {
			big_jmp[i][j] = big_jmp[i - 1][big_jmp[i - 1][j]];
			sml_jmp[i][j] = sml_jmp[i - 1][sml_jmp[i - 1][j]];
		}

	vector<int> ord(n);
	for (int i = 1; i <= n; i++)
		ord[n - a[i]] = i;

	for (auto u : ord)
		h[u] = h[sml_jmp[0][u]] + 1;
}

inline int lca(int u, int v) {
	if (h[u] > h[v]) swap(u, v);
	for (int i = 18; i --; )
		if (h[v] - h[u] >> i & 1)
			v = sml_jmp[i][v];
	if (u == v) return u;
	for (int i = 18; i --; )
		if (sml_jmp[i][u] ^ sml_jmp[i][v])
			u = sml_jmp[i][u], v = sml_jmp[i][v];
	return sml_jmp[0][u];
}

int minimum_jumps(int a, int b, int c, int d) {
	++ a, ++ b, ++ c, ++ d; // to 1-based

	int u = lca(a, b), v = lca(c, d), res = 0;
	{
		int possible = lca(u, v);
		if (possible != v) return -1;
	}

	for (int i = 18; i --; )
		if (h[big_jmp[i][u]] >= h[v]) {
			res += 1 << i;
			u = big_jmp[i][u];
		}

	if (c <= u && u <= d)
		return res;

	for (int i = 18; i --; )
		if (h[sml_jmp[i][u]] >= h[v] && sml_jmp[i][u] < c) {
			res += 1 << i;
			u = sml_jmp[i][u];
		}

	return res + 1;
}

컴파일 시 표준 에러 (stderr) 메시지

jumps.cpp: In function 'int lca(int, int)':
jumps.cpp:50:12: warning: suggest parentheses around '-' inside '>>' [-Wparentheses]
   50 |   if (h[v] - h[u] >> i & 1)
      |       ~~~~~^~~~~~

• Subtask 1: 4 / 4
• Subtask 2: 0 / 8
• Subtask 3: 0 / 13
• Subtask 4: 0 / 12
• Subtask 5: 23 / 23
• Subtask 6: 0 / 21
• Subtask 7: 0 / 19