This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "dungeon2.h"
#include <bits/stdc++.h>
using namespace std;
int n;
int deg[40002];
int par[40002], prvNum[40002];
int idx[40002], origCnt;
int origLst[40002];
vector<int> link[40002];
vector<int> toRoot[40002];
bool isOriginal[40002];
int num[40002];
int dfs(int x, int parNum = -1){
// printf("dfs %d %d\n", x, parNum);
prvNum[x] = LastRoad();
deg[x] = NumberOfRoads();
if(Color() != 1){ /// 이미 방문한 정점
int ret = Color();
Move(LastRoad(), Color());
return ret;
}
isOriginal[x] = 1;
idx[x] = ++origCnt;
origLst[origCnt] = x;
for(int i=1; i<=deg[x]; i++){
if(i == prvNum[x]){
par[x] = parNum;
link[x].push_back(parNum);
toRoot[x].push_back(1);
continue;
}
Move(i, 2);
link[x].push_back(++n);
int tmp = dfs(n, x);
toRoot[x].push_back(tmp==2);
}
if(prvNum[x] > 0) Move(prvNum[x], 3);
return 3;
}
int getBit(int x, int y){
while(y--) x/=3;
return x%3+1;
}
int pow3[] = {1, 3, 9, 27, 81, 243};
void dfs2(int x, int bit){
// printf("dfs2 %d %d\n", x, bit);
if(isOriginal[x]){ /// 고유한 정점
num[x] = x;
for(int i=1; i<=deg[x]; i++){
if(i==prvNum[x] || toRoot[x][i]) continue;
Move(i, getBit(idx[x], bit));
dfs2(link[x][i], bit);
}
if(prvNum[x] > 0) Move(prvNum[x], getBit(idx[x], bit));
}
else{
num[x] += (Color() - 1) * pow3[bit];
Move(LastRoad(), Color());
}
}
int dist[1002][1002];
int ans[1002];
void Inspect(int R){
for(int i=0; i<=40000; i++) link[i].push_back(0), toRoot[i].push_back(0);
dfs(++n);
for(int i=0; i<6; i++){
dfs2(1, i);
}
for(int i=0; i<=1000; i++) for(int j=0; j<=1000; j++) if(i!=j) dist[i][j] = 1e9;
for(int i=1; i<=origCnt; i++){
for(auto y: link[origLst[i]]){
if(y==0) continue;
// printf("%d %d\n", i, isOriginal[y] ? idx[y] : num[y]);
dist[i][isOriginal[y] ? idx[y] : num[y]] = 1;
dist[isOriginal[y] ? idx[y] : num[y]][i] = 1;
}
}
for(int k=1; k<=origCnt; k++){
for(int i=1; i<=origCnt; i++){
for(int j=1; j<=origCnt; j++){
dist[i][j] = min(dist[i][j], dist[i][k] + dist[k][j]);
}
}
}
for(int i=1; i<=origCnt; i++) for(int j=i+1; j<=origCnt; j++) ans[dist[i][j]]++;
for(int i=1; i<=R; i++) Answer(i, ans[i]);
}
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