제출 #532831

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
532831		hhhhaura	Football (info1cup20_football)	C++14	100 / 100	38 ms	2192 KiB

football

#define wiwihorz
#include <bits/stdc++.h>
#pragma GCC optimize("Ofast")
#pragma GCC target("sse")
#pragma loop-opt(on)
#define rep(i, a, b) for(int i = a; i <= b; i ++)
#define rrep(i, a, b) for(int i = b; i >= a; i--)
#define ceil(a, b) ((a + b - 1) / (b))
#define all(x) x.begin(), x.end()
#define int long long int
#define lld long double
#define pii pair<int, int>
#define random mt19937 rnd(chrono::steady_clock::now().time_since_epoch().count())
using namespace std;
#define INF 1000000000000000000
#define MOD 1000000007
#define eps (1e-9)

#ifdef wiwihorz
#define print(a...) cerr<<"Line "<<__LINE__<<":",kout("[" + string(#a) + "] = ", a)
void vprint(auto L, auto R) { while(L < R) cerr << *L << " \n"[next(L)==R], ++L;}
void kout() { cerr << endl; }
template<class T1, class ... T2> void kout(T1 a, T2 ... e) { cerr << a << " ", kout(e...);} 
#else
#define print(...) 0
#define vprint(...) 0
#endif

signed main() {
	ios::sync_with_stdio(false), cin.tie(0);
	int t; cin >> t;
	string ans = "";
	while(t--) {
		int n, k, lg;
		cin >> n >> k;
		lg = 32 - __builtin_clz(k);
		vector<int> cnt(lg + 1, 0);
		rep(i, 1, n) {
			int x; cin >> x;
			rep(j, 0, lg) {
				int val = (1ll << j);
				cnt[j] += x / val;
			}
		}
		int yes = 0;
		rep(i, 0, lg) if((1ll << i) <= k){
			if(cnt[i] & 1) {
				yes = 1;
				break;
			}
		}
		ans += (yes ? "1" : "0");
	}
	cout << ans << "\n";
	return 0;
}

컴파일 시 표준 에러 (stderr) 메시지

football.cpp:5: warning: ignoring '#pragma loop ' [-Wunknown-pragmas]
    5 | #pragma loop-opt(on)
      | 
football.cpp:21:13: warning: use of 'auto' in parameter declaration only available with '-fconcepts-ts'
   21 | void vprint(auto L, auto R) { while(L < R) cerr << *L << " \n"[next(L)==R], ++L;}
      |             ^~~~
football.cpp:21:21: warning: use of 'auto' in parameter declaration only available with '-fconcepts-ts'
   21 | void vprint(auto L, auto R) { while(L < R) cerr << *L << " \n"[next(L)==R], ++L;}
      |                     ^~~~

• Subtask 1: 26 / 26
• Subtask 2: 8 / 8
• Subtask 3: 11 / 11
• Subtask 4: 8 / 8
• Subtask 5: 16 / 16
• Subtask 6: 16 / 16
• Subtask 7: 7 / 7
• Subtask 8: 8 / 8