제출 #532676

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
532676		safaricola	A Difficult(y) Choice (BOI21_books)	C++17	0 / 100	1 ms	968 KiB

books

#include <bits/stdc++.h>
#include "books.h"
using namespace std;
typedef long long ll;
typedef pair<ll,ll> ii;
//
// --- Sample implementation for the task books ---
//
// To compile this program with the sample grader, place:
//     books.h books_sample.cpp sample_grader.cpp
// in a single folder and run:
//     g++ books_sample.cpp sample_grader.cpp
// in this folder.
//
void solve(int N, int K, long long A, int S) {
    // TODO implement this function
    ll b[N+5];
    memset(b,0,sizeof(b));
    int low = 0, high = N + 1;
    while(high - low >= 2)
    {
        int mid = (high + low) / 2;
        b[mid]=skim(mid);
        if(b[mid] < A) low = mid;
        else high = mid;
    }
    ll a[K+5];
    memset(a,0,sizeof(a));
    //cout<<low<<endl;
    high=low;
    if(high>K+2)impossible();
    for(int i=1; i<=K; i++){
        if(!b[i])b[i]=skim(i);
        a[i]=a[i-1]+b[i];
    }
    int c[K+5];
    memset(c,0, sizeof(c));
    for(int i=high-K+1; i<=high; i++){
        if(!b[i])b[i]=skim(i);
        c[i-(high-K)]=c[i-(high-K)-1]+b[i];
    }
    if(!b[high+1]) skim(high+1);
    ll cur= b[high+1];
    if(b[high+1]+a[K-1]<2*A){
        vector<int> v;
        for(int i=1; i<=K-1; i++){
            v.push_back(i);
        }
        v.push_back(high+1);
        answer(v);
    }else{
        for(int i=0; i<K;i++){
            //printf("i=%d, sum=%lld \n", i,a[i]+c[K-i]);

            if(a[i]+c[K-i]>=A && a[i]+c[K-i]<=2*A){
                vector<int> v;
                for(int j=1; j<=i; j++){
                    v.push_back(j);
                }
                for(int j=0; j<K-i; j++){
                    v.push_back(high-j);
                }
                answer(v);
            }
        }
    }
    impossible();
}

컴파일 시 표준 에러 (stderr) 메시지

books.cpp: In function 'void solve(int, int, long long int, int)':
books.cpp:43:8: warning: unused variable 'cur' [-Wunused-variable]
   43 |     ll cur= b[high+1];
      |        ^~~

• Subtask 1: 0 / 5
• Subtask 2: 0 / 15
• Subtask 3: 0 / 10
• Subtask 4: 0 / 15
• Subtask 5: 0 / 15
• Subtask 6: 0 / 20
• Subtask 7: 0 / 20