Submission #532459

#	Time	Username	Problem	Language	Result	Execution time	Memory
532459		prvocislo	Linear Garden (IOI08_linear_garden)	C++17	100 / 100	99 ms	5324 KiB

linear_garden

#include <algorithm>
#include <bitset>
#include <cassert>
#include <chrono>
#include <cmath>
#include <deque>
#include <iomanip>
#include <iostream>
#include <map>
#include <queue>
#include <random>
#include <set>
#include <string>
#include <vector>
typedef long long ll;
using namespace std;

int m;
void upd(int& a, int b) { a = (a + b) % m; }
int add(int a, int b) { return (a + b) % m; }
int mul(int a, int b) { return (a * 1ll * b) % m; }

const int maxn = 1e6 + 5;
// dp[kde som][s cim som skoncil][co malo ako posledne dva kusy][nasledujeme ten povodny retazec]
int dp[2][3][3][2], v[maxn];
int main()
{
    ios::sync_with_stdio(false);
    cin.tie(0);
    int n;
    cin >> n >> m;
    for (int i = 1; i <= n; i++)
    {
        char c;
        cin >> c;
        v[i] = (c == 'P');
    }
    dp[0][2][2][1] = 1;
    for (int i = 0; i < n; i++)
    {
        for (int j = 0; j < 3; j++) for (int k = 0; k < 3; k++) for (int l = 0; l < 2; l++) dp[!(i & 1)][j][k][l] = 0;
        for (int lst = 0; lst <= 2; lst++)
        {
            for (int lst2 = 0; lst2 <= 2; lst2++)
            {
                for (int fw = 0; fw < 2; fw++) if (dp[i & 1][lst][lst2][fw])
                {
                    for (int now = 0; now < 2 && (!fw || now <= v[i + 1]); now++)
                    {
                        if (now == lst && now == lst2) continue;
                        upd(dp[!(i & 1)][now][(now == lst) ? now : lst2][fw && now == v[i + 1]], dp[i & 1][lst][lst2][fw]);
                    }
                }
            }
        }
    }
    int ans = 0;
    for (int lst = 0; lst <= 2; lst++)
    {
        for (int lst2 = 0; lst2 <= 2; lst2++)
        {
            for (int fw = 0; fw < 2; fw++)
            {
                upd(ans, dp[n & 1][lst][lst2][fw]);
            }
        }
    }
    cout << ans << "\n";
    return 0;
}

• Subtask 1: 2 / 2
• Subtask 2: 2 / 2
• Subtask 3: 4 / 4
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