제출 #531593

#제출 시각아이디문제언어결과실행 시간메모리
531593colazcyTorrent (COI16_torrent)C++17
31 / 100
37 ms12912 KiB
#include <iostream> #include <cassert> #include <vector> #include <functional> #define let const auto #define rep(name,beg,end) for(auto lim_##name = end,name = beg;name <= lim_##name;name++) #define per(name,beg,end) for(auto lim_##name = end,name = beg;name >= lim_##name;name--) #define repn(lim) for(auto REPN_lIM = lim,REPN = 1;REPN <= REPN_lIM;REPN++) #define debug(...) fprintf(stderr,__VA_ARGS__) #define trace() debug("line : %d, Function : %s\n",__LINE__,__FUNCTION__) constexpr int maxn = 1e5 + 10; std::vector<int> G[maxn],seq; void addedge(const int u,const int v){G[u].push_back(v);} int n,s,t; bool dfs(const int u,const int faz = -1){ seq.push_back(u); if(u == t)return true; for(let v : G[u]){ if(v == faz)continue; if(dfs(v,u))return true; } seq.pop_back(); return false; } std::pair<int,int> solve(const int lim){ // assert(seq.size() >= 2); // assert(lim >= 0); let du = seq[lim],dv = seq[lim + 1]; std::function<int(const int,const int)> dp = [du,dv,&dp](const int u,const int faz){ std::vector<int> vec; vec.reserve(G[u].size()); for(let v : G[u]){ if(u == du && v == dv)continue; if(u == dv && v == du)continue; if(v == faz)continue; vec.push_back(dp(v,u)); } int res = 0,tot = 0; std::sort(vec.begin(),vec.end(),std::greater<int>()); for(let x : vec) res = std::max(res,x + (++tot)); // debug("res = %d\n",res); return res; }; return std::make_pair(dp(s,-1),dp(t,-1)); } int main(){ // std::freopen("torrent.in","r",stdin); std::ios::sync_with_stdio(false); std::cin.tie(nullptr); std::cin >> n >> s >> t; repn(n - 1){ int u,v; std::cin >> u >> v; addedge(u,v); addedge(v,u); } dfs(s); int l = 0,r = seq.size() - 2,ans = -1; while(l <= r){ let mid = (l + r) >> 1; let [f,g] = solve(mid); if(f <= g)ans = mid,l = mid + 1; else r = mid - 1; } int out = 0x7fffffff; if(ans != -1)out = std::min(out,solve(ans).second); if(ans + 1 != (int)seq.size() - 1)out = std::min(out,solve(ans + 1).first); std::cout << out << "\n"; return 0; }
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